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2 years ago

What features form where two continental plate come together

Physics

2 answers:

saw5 [17]2 years ago

8 0

Mountains, and volcanoes I think

ExtremeBDS [4]2 years ago

3 0

Ridges, mountains, and volcanoes!

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Questions E6 a& b and E7 a&b?

erica [24]

Explanation:

6a) Work = force × distance

W = Fd

W = (60 N) (10 m)

W = 600 J

6b) Change in energy = work

ΔKE = 600 J

7a) Kinetic energy is half the mass times the square of the velocity.

KE = ½ mv²

KE = ½ (0.4 kg) (25 m/s)²

KE = 125 J

7b) Work = change in energy. When the ball is stopped, it has zero kinetic energy.

W = ΔKE

W = 0 J − 125 J

W = -125 J

8 0

2 years ago

Why does the lens need to be thicker for viewing nearby objects?

Maurinko [17]

Answer: To focus on a near object – the lens becomes thicker, this allows the light rays to refract (bend) more strongly. To focus on a distant object – the lens is pulled thin, this allows the light rays to refract slightly.

Explanation:

5 0

2 years ago

A 12 kg barrel is pulled up by a rope. The barrel accelerates at 1.2 m/s2. Find the force exerted by the rope. Show all your wor

IgorLugansk [536]

Answer:

F = 132N

Explanation:

Let the pulling force be F

Given the mass of the barrel is 12 Kg and The acceleration is 1.2 m/ $sec^2$

We know that Net Force = $mass\times acceleration$

Now net force = F - mg

F - mg = ma

F = mg + ma

F = m(a+g) = $12\times (1.2 +9.8)=132N$

Note that there will be a downward force acting on the body which is equal to mg

3 0

2 years ago

In a cup of liquid water when would water molcules stop moving

Mandarinka [93]

The the Water turns to ice. But even then they would never truly stop moving.<span />

3 0

2 years ago

Read 2 more answers

An astronaut holds a rock 100 m above surface of Planet X. The rock is then thrown upwards with a sleek of 15m/s. The rock reach

Gelneren [198K]

Answer: $5 m/s^{2}$

Explanation:

This problem is related to vertical motion, and the equation that models it is:

$y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0m$ is the rock's final height

$y_{o}=100 m$ is the rock's initial height

$V_{o}=15 m/s$ is the rock's initial velocity

$\theta=90\°$ is the angle at which the rock was thrown (directly upwards)

$t=10 s$ is the time

$g$ is the acceleration due gravity in Planet X

Isolating $g$ and taking into account $sin(90\°)=1$ :

$g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t)$ (2)

$g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s))$ (3)

$g=5 m/s^{2}$ (4) This is the acceleration due gravity in Planet X

5 0

2 years ago