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Nata [24]
2 years ago
11

Students had two batteries and two different resistors. During four trials, they build four different circuits and measure the c

ircuit’s current in Amps according to the following table.
Trial Number

Voltage (V)

Resistance (Ω)

Current (A)

1

1.5

200


2

1.5

100


3

3.0

200


4

3.0

100




For which trial would the students measure the smallest current in the circuit? (AKS 10a)



A.
Trial 1

B.
Trial 2

C.
Trial 3

D.
Trial 4
Physics
1 answer:
Darina [25.2K]2 years ago
5 0

Answer:

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Explanation:

bh hi h bhi vc di oh x At jb jo iv hp of di of dr hi o hc x gh ki vc hi jo

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Answer:

a = 2.94 m/s²

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