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erma4kov [3.2K]
3 years ago
10

What poisonous gas is found in the exhaust fumes of car engines?

Chemistry
2 answers:
Xelga [282]3 years ago
6 0
The poisonous gases found in the exhaust fumes of car engines are the products of combustion which are carbon dioxide and carbon monoxide. They are known to be toxic and carcinogenic. Hope this answers the question. Have a nice day.
Ugo [173]3 years ago
4 0
The toxic gar expelled from the reaction between gasoline and oxygen in the vehicle's engine is both Carbon dioxide and monoxide
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A population of large predator
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they will eat a lot of fish and make other animals go hungry

Explanation:

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3 years ago
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Hydrochloric acid (HCl) and potassium hydroxide (KOH) react together in an aqueous solution. The reaction is an example of _____
artcher [175]
<span>A neutralization reaction.</span>
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Lakes that have been acidified by acid rain can be neutralized by limiting the addition of limestone how much limestone is requi
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From the given pH, we calculate the concentration of H+:
     [H+] = 10^-pH = 10^-5.5
We then use the volume to solve for the number of moles of H+:
     moles H+ = 10^-5.5M * 4.3x10^9 L =  13598 moles
From the balanced equation of the neutralization of hydrogen ion by limestone written as
     CaCO3(s) + 2H+(aq)  → Ca2+(aq) + H2CO3(aq)
we use the mole ratio of limestone CaCO3 and H+ from their coefficients, which is 1 mole of CaCO3 is to react with 2 moles of H+, to compute for the mass of the limestone:
     mass CaCO3 = 13598mol H+(1mol CaCO3/2mol H+)
                               (100.0869g CaCO3/1mol CaCO3)(1kg/1000g) 
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3 years ago
1. A 205 g sample of H20 at 25.0 °C is heated until the temperature reaches 75.0 °C. How many
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3 years ago
Density is the ratio of a sample's mass to its volume. A bar of lead has a mass of 115.2 g. When it is submerged in 25.0 mL of w
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Answer:

$10.97 \ g/cm^3$

Explanation:

Given :

Mass of a bar of lead = 115.2 g

Initial water level $\text{in the graduated cylinder}$ = 25 mL

Final water level $\text{in the graduated cylinder}$ = 35.5 mL

Difference in the water level = 35.5 - 25

                                               = 10.5 mL

                                               = 10.5 \ cm^3

We know that when a body is submerged in water, it displaces its own volume of water.

Therefore, the volume of the lead bar = volume of the water displaced = 10.5 mL  = 10.5 \ cm^3

We know that mathematically, density is the ratio of mass of body to its volume.

Density of the lead bar is given by :

$\rho =\frac{\text{mass}}{\text{volume}}$

$\rho =\frac{\text{115.2 g}}{\text{10.5 cm}^3}$

  = $10.97 \ g/cm^3$

3 0
3 years ago
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