Answer:
Al(s) ⇄ Al³⁺(aq) + 3e⁻ (oxidation)
Mg⁺²(aq) + 2e⁻ ⇄ Mg(s) (reduction)
Explanation:
In the cell notation, first is placed the anode and then the cathode, so Al(s) is in the anode, where an oxidation reaction is taking place, and Mg²⁺ is in the cathode, where a reduction reaction is taking place. The half-reactions are:
Al(s) ⇄ Al³⁺(aq) + 3e⁻ (oxidation)
Mg⁺²(aq) + 2e⁻ ⇄ Mg(s) (reduction)
For the global reaction, it'll be necessary that the number of electrons (e⁻) is equal in the half-reactions, so the first one is multiplied by 2 and the second by three and the global reaction is:
2Al(s) + 3Mg⁺²(aq) ⇄ 2Al³⁺(aq) + 3Mg(s)
Answer:
well idk but i will take the points
Explanation:
The heat lost by the beads is equal to the heat gained by the water. The specific heat capacity of water is 4.18 joules/gram. "w" will denote water's property and "b" will denote the beads' properties.
mw x Cpw x ΔTw = -mb x Cpb x ΔTb
100 x 4.18 x (29.9 - 25) = 34.5 x Cpb x (100 - 29.9)
Cpb = 0.84 joules/gram
Answer:
Option C. Gain 1 electron
Explanation:
Valence electron(s) are the electron(s) located on the outermost shell of an atom. Valency is simply defined as the combining power of an atom.
Chlorine (Cl) atom has 7 valence electron. This implies that Cl needs just one electron to complete it's octet configuration. It will be difficult for Cl to lose any of it's valence electron(s). Cl can either gain or share 1 electron to become stable.
Thus, considering the options given in the question above, option C gives the correct answer to the question.
