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Leni [432]
3 years ago
11

Why does the same side of the moon always face earth? A. The rotational period of earth is the same as that of the moon B. The r

otational period of earth is equal to one revolution around earth C The rotational period of the moon is equal to one revolution around earth D. The rotational period of the moon is different than one revolution around Earth
Chemistry
2 answers:
mixer [17]3 years ago
3 0

Answer: A. the rotational period of the earth is the same as that of the moon

MrMuchimi3 years ago
3 0

Answer:

they rotate at the same time period it ook the test

Explanation:

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Why boron trifluoride is nonpolar and sulphur dioxide is polar
ella [17]

it small because that bond is not very polar notice that all of those arrows they cancel. because they point in opposite directions. that's why BH 3 is nonpolar if we were to draw the Lewis structure of bf3. ... so even though the boron fluorine bond is polar the molecule as a whole is nonpolar.

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3 years ago
How do the test variables (independent variables) and outcome variables (dependent variables) in an experiment compare? A. The o
SVETLANKA909090 [29]

Answer:

C.

Explanation:

8 0
3 years ago
Read 2 more answers
What is the total number of oxygen atoms on the right-hand side of this chemical equation?
vivado [14]

The chemical equation is

Cu(s) +4HNO3(aq) ⇒ Cu(NO3)2(aq) + 2NO2(g) + 2H2O(g)

Answer:

12

Explanation:

In the right hand side of the equation, there are three compound which contains O2, which are;

Cu(NO3)2 , number of oxygen atoms =3*2 =6

2NO2, number of oxygen atoms = 2*2=4

2H2O, number of oxygen atoms =2*1=2

Total number of oxygen atoms on the right side of equation = 6+4+2 =12

8 0
3 years ago
How can mushrooms grow without harming trees?
son4ous [18]
It depends on the species because most mushrooms help by sharing the phosphorus with the tree
4 0
3 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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5 0
1 year ago
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