Answer:
410.196 J/[kg*°C].
Explanation:
1) the equation of the energy is: E=c*m*(t₂-t₁), where E - energy (523 J), c - unknown specific heat of copper, m - mass of this copper [kg], t₂ - the final temperature, t₁ - initial temerature;
2) the specific heat of copper is:
![c=\frac{E}{m*(t_2-t_1)}; \ => \ c=\frac{523}{0.085*(45-30)}=\frac{523}{1.275}=410.196[\frac{J}{kg*C}].](https://tex.z-dn.net/?f=c%3D%5Cfrac%7BE%7D%7Bm%2A%28t_2-t_1%29%7D%3B%20%5C%20%3D%3E%20%5C%20c%3D%5Cfrac%7B523%7D%7B0.085%2A%2845-30%29%7D%3D%5Cfrac%7B523%7D%7B1.275%7D%3D410.196%5B%5Cfrac%7BJ%7D%7Bkg%2AC%7D%5D.)
Take a zip lock bag and draw clouds on the outside with a sharpie then fill the bag with water and then tape it on a window that has a lot of sun and wait awhile and there should be a change in the water and that shooed what happens to water when it’s warm/sunny out
Explanation:
Fe. O
72.40/ 56 27.60/16
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1.29/1.29 1.725/1.29
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1. :. 1
<h3>Emperical formula = FeO</h3>
The answer to your question is,
B. Government.
-Mabel <3
