BaCl₂(aq) + Na₂SO₄(aq) = BaSO₄(s) + 2NaCl(aq)
Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) = BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)
Ba²⁺(aq) + SO₄²⁻(aq)= BaSO₄(s)
Answer:
1-Fluoro-4-nitrobenzene
Step-by-step explanation:
Step 1. Identify the substituents on the ring,
The groups are <em>fluoro</em> and <em>nitro</em>. They have no priority as functional groups, so the base name is <em>benzene</em>.
Step 2. Identify their relative priorities.
F and NO₂ have no functional group priority, so we list them in alphabetical order. F has <em>alphabetical priority </em>over NO₂. The name becomes <em>fluoronitrobenzene</em>.
Step 3. Number the atoms of the ring.
The C atom bearing the F is <em>C1.</em> Count around the ring, and the NO₂ group is on <em>C4</em>.
Step 4. Name the compound.
Insert the locating numbers <em>immediately in front</em> of the substituents. Use <em>hyphens</em> to join letters to numbers.
The name becomes 1-fluoro-4-nitrobenzene.
Hello!
1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?
- <u><em>We have the following data:</em></u>
Vo (initial volume) = 1.00 L
V (final volume) = 473 mL → 0.473 L
Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)
P (final pressure) = ? (in atm)
- <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>






<u><em>Answer: </em></u>
<u><em>The new pressure of the gas is 2.11 atm </em></u>
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