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3 years ago

A compound has a molar mass of 44.01 g/mol. What is its identity?

1 answer:

6 0

This problem is very vague since no other details are given. However for the sake of calculation let us assume that the compound is an ideal gas at STP.

So that the molar volume is: 1 mole = 22.4 L

<span>density = (44.01 g/mol) * (1 mol / 22.4 L) = 1.96 g/L = 1.96 kg/m^3</span>

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Answer : The formal charge on the C is, (-1) charge.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $CH_3^{-1}$

As we know that carbon has '4' valence electrons and hydrogen has '1' valence electron.

Therefore, the total number of valence electrons in $CH_3^{-1}$ = 4 + 3(1) + 1 = 8

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Now we have to determine the formal charge on carbon atom.

Formula for formal charge :

$\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}$

$\text{Formal charge on C}=4-2-\frac{6}{2}=-1$

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