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Ahat [919]
3 years ago
8

If p∥q, m∠1=5b+23, and m∠11=2b+10, find m∠2, m∠4, m∠10, and m∠12.

Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

tgtutyffyfyfyfyfydryd7dudududyfyf7

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Area of the living room is 180 square feet and the perimeter is 54 feet. What are the dimensions in feet?
dolphi86 [110]

Answer.....15ft by 12ft

Explanation:

Area = Length × Width

180 = LW....make W the subject of formula

;W = 180/L

Perimeter = 2L + 2W

54 = 2L + 2(180/L)...sub W with the formula above...

then simplify the equation and obtain...

2L^2 - 27L + 180 = 0....then solve using the quadratic formula....then obtain..

;L = 15ft....after obtaining L = 15...then substitute into the W = 180/L equation...

where W = 180/15 = 12ft

there you have...Length = 15ft and Width = 12ft

5 0
3 years ago
Can someone explain how to do this
jolli1 [7]

Answer:

20%

Step-by-step explanation:

im not really good at percentages but from what i know you first make it a fraction by adding all the numbers together to get 55(denominator). then for the numerator you take the section that they want(11). 11/55 is equal to 20/100(divide 100 by 55 and multiply the quotient by 11 to get 20). 20/100 is 20%. hope this kinda helps.

7 0
3 years ago
Which of these is an exponential parent function?
attashe74 [19]
The exponential parent function is D
3 0
3 years ago
If 20 were added to each of the vlaues in a data set that originally had a standard deviation of 8, the standard deviation of th
Nitella [24]

Answer:

False (I assume it's a true/false question)

Step-by-step explanation:

Standard deviation measures how spread out the data is.  If you add 8 to all the data values, the distribution of data moves to the right (on a graph) 8 units. The shifted data are no more and no less spread out than before.  The standard deviation does not change.

3 0
4 years ago
Express p in terms of q if
Irina-Kira [14]

p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)

q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}

8 0
3 years ago
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