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Ahat [919]
3 years ago
8

If p∥q, m∠1=5b+23, and m∠11=2b+10, find m∠2, m∠4, m∠10, and m∠12.

Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

tgtutyffyfyfyfyfydryd7dudududyfyf7

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joja [24]
the answer should be 44. you plug in -7 for x.
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Simply the given expressions below.
Setler [38]

Step-by-step explanation:

a) 4x + 8 - 2x + 7

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Line ET is tangent to circle A and T, and the measure of arc TG is 46 degrees. What is the measure of Angle GET
kogti [31]

Answer:

m\angle GET=67^o

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

The measure of the external angle is the semi-difference of the arches it covers.

so

m\angle GET=\frac{1}{2}[arc\ TN-arc\ TG]

Remember that the diameter divide the circle into two equal parts

In this problem

TN is a diameter

we have

arc\ TN=180^o ----> because is half the circle (TN is a diameter)

arc\ TG=46^o ---> is given

substitute

m\angle GET=\frac{1}{2}[180^o-46^o]=67^o

7 0
3 years ago
Need help with school
denpristay [2]

Answer: 139°

Reasoning:

Angle 3 and 5 are congruent, so you can put their expressions equal to each other and solve.

14x-1=9x+14

To isolate the x to one side, subtract the 9x from the 14x.

5x-1=14

Now to get the constants on one side, add the 1 to the 14.

5x=15

Now divide both sides by 5 to isolate the x.

5x/5=15/5

x=3

Now that we know that, we can figure out angle 3.

9(3)+14

27+14= 41

Angle 3 = 41°

Now that we know what angle 3 is, we can subtract it from 180° to figure out angle 8 since angle 3 and 8 are supplemtary angles, aka linear pairs.

180°- 41°= 139°

<h3>Double checking your answer:</h3>

41°+139°=180°

3 0
3 years ago
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