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Natasha_Volkova [10]
3 years ago
15

PLEASEEEEEEE HELP ITs SUPER IMPORTANT I NEED IT PRETTY PLEASE

Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

c I think I hope it helps

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Where is most of the high-level waste from nuclear reactors stored?
Nana76 [90]
It's stored at the reactor site.
7 0
3 years ago
_____ stars can be between one thousand times dimmer and one million times brighter than the Sun.
dmitriy555 [2]

Answer:

The answer is

D. Main sequence

Explanation:

Main sequence stars can be between one thousand times dimmer and one million times brighter than the Sun.

What is main sequence stars?

A main sequence star is any star that is fusing hydrogen in its core and has a stable balance of outward pressure from core nuclear fusion and gravitational forces pushing inward.

6 0
3 years ago
In a nuclear reaction, the energy released is equal to 8.1 x 1016 joules. Calculate the mass lost in this reaction. (1 J = 1 kg
makvit [3.9K]
Use the formula E=mc^2
energy given=<span>8.1 x 10^16 joules
</span>speed of <span>light = 3.00 × 10^8 m/s
</span>
plug in the values we'll get mass=<span>9.0 x 10-1 kg</span>

5 0
3 years ago
Read 2 more answers
What volume and mass of steam at 100 Celsius and 760. torr (or 1 atm) would release the same amount of energy as heat during con
erastova [34]
  
<span>As we know that
1 cu cm H2O = 1 mL H2O = 1g H2O 
now

Heat of fusion of water = 79.8 cal/g 
and

Heat of vaporization of water = 540 cal/g 

Atomic weight of water : H=1 O=16 H2O=18 
now by calculating and putting values

65.5gH2O x 79.8cal/gH2O x 1gH2O/540cal = 9.68g H2O (steam) 

9.68gH2O x 1molH2O/18gH2O x 22.4LH2O/1molH2O = 12.0 L H2O
hope it helps</span>
3 0
3 years ago
Read 2 more answers
0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction which ensues is: 2Al(OH)3(s) +
Veseljchak [2.6K]

Answer:

The answer to your question is 1.1 moles of water

Explanation:

                     2Al(OH)₃  +   3H₂SO₄   ⇒   Al₂(SO₄)₃  +   6H₂O

                       0.45 mol      0.55 mol                                ?

Process

1.- Calculate the limiting reactant

Theoretical proportion

       Al(OH)₃ / H₂SO₄ = 2/3 = 0.667

Experimental proportion

       Al(OH)₃ / H₂SO₄ = 0.45 / 0.55 = 0.81

From the proportions, we conclude that the limiting reactant is H₂SO₄

2.- Calculate the moles of H₂O

                        3 moles of H₂SO₄ ----------------  6 moles of water

                        0.55 moles of H₂SO₄ -----------    x

                        x = (0.55 x 6) / 3

                        x = 3.3 / 3

                       x = 1.1 moles of water

5 0
3 years ago
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