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xxTIMURxx [149]
3 years ago
10

Can someone help me with this please What is the right answer for it?

Mathematics
2 answers:
kondaur [170]3 years ago
8 0
That would be 3 or 4 cm
Amiraneli [1.4K]3 years ago
6 0
8x(7+8)=10x(10+AB)
120=10x(10+AB)
12-2=AB
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12 and 1/8, I just simplified 2/16 to 1/8
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The average rate of change of f(t) from t=2 to t=6 is
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3 years ago
The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds
Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 50

Find the probability that he weighs between 170 and 220 pounds.

This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{50}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 170

Z = \frac{X - \mu}{\sigma}

Z = \frac{170 - 200}{50}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

6 0
3 years ago
George had $15. He bought a shirt on sale for $6. Which decimal is equivalent to the fraction of money George has left
Over [174]

Answer:

.9

Step-by-step explanation:

15-6=9

3 0
3 years ago
What value of c makes this proportion true 25/20= x/4
satela [25.4K]

x = 5

HOPE THIS WILL HELP U

5 0
3 years ago
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