I believe that the number for Co2 in 220 grams is 5
Answer:
8.75 mL
Explanation:
First, we calculate the molar mass of NaCl = molar mass of Na + molar mass of Cl. Molar mass of Na = 23 g/mol, molar mass of Cl = 35.5 g/mol.
So molar mass NaCl = (23 + 35.5) g/mol = 58.5 g/mol. The number of moles ,n of NaCl in 12.5g is n = mass of NaCl/ molar mass NaCl = 12.5 g / 58.5 g/mol = 0.214 mol.
The molarity, M of 150 mL M = number of moles/ volume = 0.214 mol / 150 mL = 1.427 M.
We now calculate the number of moles of NaCl in 250 mL of 0.500 M.
Number of moles, n = molarity × volume. molarity = 0.500 M, volume = 250 mL. So n = 0.500 × 250 = 0.125 moles. Since we have 0.125 moles in the dilute 250 mL solution, the volume of the 150 mL 1.43 M solution required is number of moles in 250 mL solution/molarity of 150 mL solution = 0.125 mol / 1.427 M = 0.0875 L = 8.75 mL
Answer:
The answer to your question is P2 = 280 mmHg
Explanation:
Data
Pressure 1 = P1 = 400 mmHg
Volume 1 = V1 = 1.75 L
Pressure 2 = ?
Volume 2 = 2.5 L
Process
1.- Use Boyle's law to solve this problem
P1V1 = P2V2
-Solve for P2
P2 = P1V1 / V2
2.- Substitution
P2 = (400)(1.75) / 2.5
3.- Simplification
P2 = 700 / 2.5
4.- Result
P2 = 280 mmHg
Answer:
Explanation:
Answer 1:
Lithium : 1s2 2s1 Fluorine: 1s2 2s2 2p5 Carbon: 1s2 2s2 2p2
Argon : 1s2 2s2 2p6 3s2 3p6 Sulphur: 1s2 2s2 2p6 3s2 3p4
Nickel: 1s2 2s2 2p6 3s2 3p6 3d8 4s2 Rubidium: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s1 Xenon: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6
Answer 2: A. Fluorine B. Calcium
C. It is Tellurium if this was the exact electronic configuration 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4 you intend to write, if not, no element has such electonic configuration.
D. Bromine but the correct electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5
C2H5OH + 3O2 = 2CO2 + 3H2O