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skad [1K]
3 years ago
10

What type(s) of intermolecular forces are expected between seh2 molecules?

Chemistry
2 answers:
bija089 [108]3 years ago
7 0
London dispersion
dipole-dipole
olga_2 [115]3 years ago
3 0

Answer:

Induced and dipole forces.

Explanation:

Hello,

Due to its structure, SeH_2, one identifies the following two intermolecular forces:

- Induced: Ion-Induced Dipole Forces

At first, an ion-induced dipole attraction is present as a weak force which results when the approach of an ion induces a dipole in this nonpolar molecule by disturbing the arrangement of electrons.

- Dipole forces.

Now, dipole-dipole forces are present in such molecule as attractive forces between the positive end of one of the polar molecule and the negative end of another polar space in the molecule.

Best regards.

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Answer:

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3 years ago
If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + NaI → PbI2 + NaNO3
ss7ja [257]

Answer:- 27.7 grams of PbI_2 are produced.

Solution:- The balanced equation is:

Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16)  = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})

= 39.0gPbI_2

18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})

= 27.7gPbI_2

From above calculations, NaI gives least amount of PbI_2, so the answer is, 27.7 g of PbI_2 are produced.

8 0
3 years ago
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6 0
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Gaseous ethane CH3CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.6
yulyashka [42]

Answer:

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Explanation:

Step 1: Write the balanced equation

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Step 2: Determine the limiting reactant

The theoretical mass ratio of CH₃CH₃ to O₂ is 30.06:112.0 = 0.2684:1.

The experimental mass ratio of CH₃CH₃ to O₂ is 0.60:3.52 = 0.17:1.

Thus, the limiting reactant is CH₃CH₃

Step 3: Calculate the mass of CO₂ produced

The theoretical mass ratio of CH₃CH₃ to O₂ is 30.06:88.02.

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