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Sergeu [11.5K]
3 years ago
8

Which statements accurately compare the environmental impact of acquiring natural gas and acquiring oil? Select the two correct

answers.
Both can cause landslides on mountains.
Both can cause sinkholes to occur.
Both can impact groundwater supply.
Both emit hydrogen into the air.
Both involve drilling into the earth.
Giving extra points and giving brainist!
Chemistry
2 answers:
solmaris [256]3 years ago
6 0

Answer:

Both involve drilling into the earth and can cause environmental degradation.

Explanation:

likoan [24]3 years ago
5 0

Answer:

Both can impact groundwater supply.

Both involve drilling into the earth.

Explanation:

Crude oil and natural gas (Hydrocarbon) are found in the earth crust , therefore drilling this liquid gold require some level of expertise to drill it .

Crude oil are formed in rocks called source rocks(shale) . This source rocks posses the necessary or right environment were this hydrocarbon could be formed for example abundant of organic matter. The hydrocarbon may then migrate to a reservoir rocks(sandstone) were it can be drilled.  so, mining this rocks involves drilling into the earth to get the hydrocarbon.

Inappropriate drilling practice can result to spilling of this hydrocarbon to ground water .  If the reservoir rocks which usually acts as a cap rock or limitation to movement of crude oil loose it ability the oil or gas may migrate further and contaminate ground water.

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2. Bart finds a solid shiny
notsponge [240]

Answer:

1. Density of metal object = <em><u>11000 kg / m3</u></em>.

2. Could the object be gold = <em><u>No,because the density of gold is 19300 kg / m3</u></em>.

7 0
3 years ago
Is mixing butter, granulated sugar, and brown sugar until it's creamy a physical or chemical change and why
Nadusha1986 [10]

Answer:

Physical

Explanation: Because it says "Until creamy" meaning you're changing the look, not the way it reacts with each other.

8 0
3 years ago
Read 2 more answers
Ethylene oxide (EO) is prepared by the vapor-phase oxidation of ethylene. Its main uses are in the preparation of the antifreeze
Rashid [163]

Answer:

a. ΔH^0_{rxn} = -108.0\frac{kJ}{mol}

b. 320.76° C

Explanation:

a.)

we can solve this type of question (i.e calculate ΔH^0_{rxn} , for the gas-phase reaction )  using the Hess's Law.

ΔH^0_{rxn} =  E_{product} deltaH^0_{t}-E_{reactant} deltaH^0_{t}

Given from the question, the table below shows the corresponding  ΔH^0_{t}(kJ/mol) for each compound.

Compound                    H^0_{t}(kJ/mol)

Liquid EO                       -77.4

CH_4_(g_)                            -74.9                

CO_(g_)                              -110.5

If we incorporate our data into the above previous equation; we have:

ΔH^0_{rxn} = (-110.5 kJ/mol + (-74.9 kJ/mol) ) - (-77.4 kJ/mol)

          =   -108.0 \frac{kJ}{mol}

b.)

We are to find the final temperature if the average specific heat capacity of the products is 2.5 J/g°C

Given that:

the specific heat capacity (c) = 2.5 J/g°C

T_{initial} = 93.0°C   &

the  enthalpy of vaporization  (ΔH^0_{vap}) = 569.4 J/g

If, we recall; we will remember that; Specific Heat Capacity is the amount of heat needed to raise the temperature of one gram of a substance by one kelvin.

∴ the specific heat capacity (c) is given as =  \frac{Heat(q)}{mass*changeintemperature(T_{initial}-T_{final})}

Let's not forget as well, that  ΔH^0_{vap} = \frac{q}{mass}

If we substitute  ΔH^0_{vap}  for  \frac{q}{mass} in the above equation, we have;

specific heat capacity (c) = \frac{deltaH^0_{vap}}{T_{final}-T_{initial}}

Making (T_{final}- T_{initial}) the subject of the formula; we have:

T_{final}- T_{initial}  = \frac{delat H^0_{vap}}{specificheat capacity}

(T_{final}-93.0^0C)=\frac{569.4J/g}{2.5J/g^0C}

T_{final}=\frac{569.4J/g}{2.5J/g^0C}+93.0^0C

         = 227.76°C +93.0°C

          = 320.76°C

∴ we can thereby conclude that the final temperature = 320.76°C                

7 0
3 years ago
A gas at 300 k and 4.0 atm is moved to a new loacation with a temperature of 250 k. The volume changes from 5.5 L to 2.0 L. What
alexgriva [62]
Answer is: <span>the pressure of the gas is 9,2 atm.
</span>p₁ = 4,0 atm.
T₁ = 300 K.
V₁ = 5,5 L.
p₂ = ?
T₂ = 250 K.
V₂ = 2,0 L.
Use combined gas law - the volume of amount of gas is proportional to the ratio of its Kelvin temperature and its pressure.<span> 
</span>p₁V₁/T₁ = p₂V₂/T₂.
4 atm · 5,5 L ÷ 300 K  = p₂ · 2,0 L ÷ 250 K.
0,0733 = 0,008p₂.
p₂ = 9,2 atm.

4 0
3 years ago
What are the first two quantum numbers for the electrons located in subshell 4d?
SCORPION-xisa [38]

Answer:

n = 4, l = 2

Explanation:

The number 4 in 4d is the principal quantum number (n).

The letter d in 4d tells us that we have a d orbital, as determined by the <em>secondary quantum number (l</em>).

The quantum number l tells us the shape of the orbital.

l = 0     s orbital

l = 1      p orbital

l = 2     d orbital

7 0
3 years ago
Read 2 more answers
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