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hram777 [196]
3 years ago
5

You are a drop of water going through the water cycle. Where do you go? How do you get there? What processes do you go through?

Include at least three phases of the water cycle . I do know what the phases of the water cycle,so i don't need the phases of the water cycle. I just need a righting
Chemistry
2 answers:
katovenus [111]3 years ago
7 0

Answer:

Explanation:

Hi

enyata [817]3 years ago
6 0

→Answer:

evaporation, condensation, precipitation

Explanation:

this diagram may help

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If the pKa of Lysine is 5, then at a pH of 7, it is most likely going to be a) Neutral. b) Negatively charged. c) Positively cha
Sladkaya [172]
C. Positively charged
7 0
3 years ago
What is the empirical formula of a compound that is 18.8% Li, 16.3% C , and 64.9% O
zlopas [31]

Greetings!

To find the empirical formula you need the relative atomic mass of each element!

Li = 6.9

C = 12

O = 16

You can simply change the percentages into full grams

Li = 18.8g

C = 16.3g

O = 64.9


Then you use this to find the Number of moles = amount in grams / atomic mass

Li = 18.8 ÷ 6.9 = 2.7246

C = 16.3 ÷ 12 = 1.3583

O = 64.9 ÷ 16 = 4.0562

Then divide each number of moles by the smallest value:

Li = 2.7246 ÷ 1.3583 = 2.0

C = 1.3583 ÷ 1.3583 = 1

O = 4.0562 ÷ 1.3583 = 2.9 ≈ 3


So that means that there are 2 Li, 1 C, and 3 O

Empirical formula would be:

Li₂CO₃


Hope this helps!

3 0
3 years ago
__________ ___________ can release different forms of energy such as electricity or light, in addition to the release of heat en
Stells [14]

Answer:

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Explanation:

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8 0
2 years ago
Read 2 more answers
A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what i
IRINA_888 [86]

Answer : The pressure after the temperature change is, 0.752 atm

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure = 0.82 atm

P_2 = final pressure = ?

T_1 = initial temperature = 21^oC=273+21=294K

T_2 = final temperature = -3.5^oC=273+(-3.5)=269.5K

Now put all the given values in the above equation, we get:

\frac{0.82atm}{294K}=\frac{P_2}{269.5K}

P_2=0.752atm

Thus, the pressure after the temperature change is, 0.752 atm

4 0
3 years ago
(image attached) AP CHEM ACID BASE Is my answer correct? I will mark as brainliest if you answer me. I don't need an explanation
pychu [463]

Answer:

Your answer is correct based on what I remember from AP Chemistry  

Explanation:

3 0
2 years ago
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