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disa [49]
3 years ago
11

A transverse wave is observed to be moving along a lengthy rope. Adjacent crests are positioned 2.4 m apart. Exactly six crests

are observed to move past a given point along the medium in 9.1 seconds. Determine the frequency of these waves
Chemistry
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

f = 0.65 hz

Explanation:

Given that,

The distance between adjacent crests, wavelength = 2.4 m

6 crests are observed to move past a given point along the medium in 9.1 seconds.

We need to find the frequency of these waves.

We know that,

Frequency = no. of waves per second.

f=\dfrac{6}{9.1}\ Hz\\\\=0.65\ Hz

So, the frequency of these waves is equal to 0.65 Hz.

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Describe the relationship between temperature and particle movement
soldi70 [24.7K]

Answer:

If matter is heated and thus its temperature rises more and more, it can be seen that the particles contained in it move ever faster – be it the relatively free movement of the particles in gases or the oscillation around a rest position in solids. The temperature of a substance can therefore be regarded as a measure of the velocity of the particles it contains. With a higher temperature and thus higher particle

Explanation:

7 0
3 years ago
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?
faltersainse [42]

Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

  • Volume of the solution (V): 500 mL
  • Molar concentration of the solution (M): 0.8 M = 0.8 mol/L

Step 2: Convert "V" to L

We will use the conversion factor 1 L = 1000 mL.

500 mL × 1 L/1000 mL = 0.500 L

Step 3: Calculate the moles of KBr (solute)

The molarity is the quotient between the moles of solute (n) and the liters of solution.

M = n/V

n = M × V

n = 0.8 mol/L × 0.500 L = 0.4 mol

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Why is acid added to water during eletrolysis
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Pure water is a non conductor of electricity and dilute acids in their aqueous solutions form free ions, which conducts electricity. Thus when we need to electrolyse water, a dilute acid is added to increase its conductivity.

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