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adoni [48]
3 years ago
13

Find the distance in units 5/8 and 1/4

Mathematics
2 answers:
Brut [27]3 years ago
6 0
Sorry I’m bad at fractions
DanielleElmas [232]3 years ago
4 0

Answer:

The chosen topic is not meant for use with this type of problem.

Step-by-step explanation:

You might be interested in
Solve 13+x>11. Enter your answer as an equality
Wittaler [7]

Answer:

x>-2

Step-by-step explanation:

13+x>11

Subtract 13 from each side

13-13+x>11-13

x>-2

5 0
3 years ago
g Which of the following is equivalent to P( A|B)? a. P(A and B) b. P(B|A) c. P(A)/P(B) d. None of these choices.
Scilla [17]

Answer:

The correct option is D.

But option B is correct if P(A) = P(B).

Step-by-step explanation:

P(A|B) is read as "The probability of A given B".

It is different from the options A, B, and C.

It is equal to option B only if the probability of A is equal to the probability of B. That is P(A|B) = P(B|A) if P(A) = P(B).

6 0
3 years ago
Place the indicated product in the proper location on the grid. [4 - (3c - 1)] [6 - 3c -1)]
mash [69]
[4 - (3c - 1)][6 - (3c - 1)]
[4 - 3c + 1][6 - 3c + 1]
[-3c + 4 + 1][-3c + 6 + 1]
[-3c + 5][-3c + 7]
-3c[-3c + 7] + 5[-3c + 7]
-3c[-3c] - 3c[7] + 5[-3c] + 5[7]
9c² - 21c - 15c + 35
9c² - 36c + 35
7 0
3 years ago
And, what is the least common multiple of 6,15, and 5
iren2701 [21]

Answer:

there is no multiplyer becuase 1 dosnt work no 2 nor3 nor4 nor5 nor6 and then you will be greater than 6 so it dosnt fit into 5 so

????/

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If $a$, $b$, $c$, and $d$ are replaced by four distinct digits from $1$ to $9$, inclusive, then what's the largest possible valu
Alexxx [7]

Answer:

70

Step-by-step explanation:

  • for the value of difference to be largest, the minuend should be maximum(most possibly) and the subtrahend should be minimum

[in A-B=X, A is minuend and B is subtrahend ]

  • so, $a.b should be maximum. as there is a condition that 4 digits should be distinct, the product will be maximum if we choose 2 maximum valued numbers from the given numbers. so, one of them should be 9 and the other should be 8.

therefore, $a.b=9*8=72

  • as mentioned above, c.d$ should be minimum. this will be possible only when we choose  2 minimum valued numbers from the given numbers. so, one of them should be 1 and the other should be 2.

therefore, c.d$ = 1*2 = 2

  • hence, the difference = 72-2 = 70
  • thus,  the largest possible value of the difference $a.b - c.d$ = 70
7 0
3 years ago
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