Answer:
Only points on the circle satisfy the given inequality.
Step-by-step explanation:
Given: Unit circle
To find: portion of the unit circle which satisfies the trigonometric inequality
Solution:
In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)
= side opposite to /hypotenuse
= side adjacent to /hypotenuse
So, coordinates of A =
For any point (x,y) on the unit circle with centre at origin, equation of circle is given by
Put
So, satisfies the equation
For points inside the circle,
For points outside the circle,
So, only points on the circle satisfy the given inequality.