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tia_tia [17]
3 years ago
12

Help !! Im not sure how to do this ​

Chemistry
1 answer:
7nadin3 [17]3 years ago
4 0
1)The third equation must be halved.
H20–>H2+1/2O2
So ΔΗ3=483.6/2
2)The second equation must be halved and reversed.
CO2–>CO+1/2O2
So ΔΗ2=-(-566)/2=566/2

And now :
C+O2–>CO2
CO2–>CO+1/2O2
H2O—>H2+1/2O2
(You add them)
C+H2O—>CO+H2
ΔΗrxn=ΔΗ1+ΔΗ2’+ΔΗ3’=-393.5+283+241,8=131,3
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