Answer:
The magnitude and direction of the acceleration of the particle is ![a= 0.3296\ \hat{k}\ m/s^2](https://tex.z-dn.net/?f=a%3D%200.3296%5C%20%5Chat%7Bk%7D%5C%20m%2Fs%5E2)
Explanation:
Given that,
Mass ![m = 1.81\times10^{-3}\ kg](https://tex.z-dn.net/?f=m%20%3D%201.81%5Ctimes10%5E%7B-3%7D%5C%20kg)
Velocity ![v = (3.00\times10^{4}\ m/s)j](https://tex.z-dn.net/?f=v%20%3D%20%283.00%5Ctimes10%5E%7B4%7D%5C%20m%2Fs%29j)
Charge ![q = 1.22\times10^{-8}\ C](https://tex.z-dn.net/?f=q%20%3D%201.22%5Ctimes10%5E%7B-8%7D%5C%20C)
Magnetic field ![B= (1.63\hat{i}+0.980\hat{j})\ T](https://tex.z-dn.net/?f=%20B%3D%20%281.63%5Chat%7Bi%7D%2B0.980%5Chat%7Bj%7D%29%5C%20T)
We need to calculate the acceleration of the particle
Formula of the acceleration is defined as
![F = ma=q(v\times B)](https://tex.z-dn.net/?f=F%20%3D%20ma%3Dq%28v%5Ctimes%20B%29)
![a =\dfrac{q(v\times B)}{m}](https://tex.z-dn.net/?f=a%20%3D%5Cdfrac%7Bq%28v%5Ctimes%20B%29%7D%7Bm%7D)
We need to calculate the value of ![v\times B](https://tex.z-dn.net/?f=v%5Ctimes%20B)
![v\times B=(3.00\times10^{4}\ m/s)j\times(1.63\hat{i}+0.980\hat{j})](https://tex.z-dn.net/?f=v%5Ctimes%20B%3D%283.00%5Ctimes10%5E%7B4%7D%5C%20m%2Fs%29j%5Ctimes%281.63%5Chat%7Bi%7D%2B0.980%5Chat%7Bj%7D%29)
![v\times B=4.89\times10^{4}](https://tex.z-dn.net/?f=v%5Ctimes%20B%3D4.89%5Ctimes10%5E%7B4%7D)
Now, put the all values into the acceleration 's formula
![a =\dfrac{1.22\times10^{-8}\times(-4.89\times10^{4}\hat{k})}{1.81\times10^{-3}}](https://tex.z-dn.net/?f=a%20%3D%5Cdfrac%7B1.22%5Ctimes10%5E%7B-8%7D%5Ctimes%28-4.89%5Ctimes10%5E%7B4%7D%5Chat%7Bk%7D%29%7D%7B1.81%5Ctimes10%5E%7B-3%7D%7D)
![a= -0.3296\ \hat{k}\ m/s^2](https://tex.z-dn.net/?f=a%3D%20-0.3296%5C%20%5Chat%7Bk%7D%5C%20m%2Fs%5E2)
Negative sign shows the opposite direction.
Hence, The magnitude and direction of the acceleration of the particle is ![a= 0.3296\ \hat{k}\ m/s^2](https://tex.z-dn.net/?f=a%3D%200.3296%5C%20%5Chat%7Bk%7D%5C%20m%2Fs%5E2)
Answer:
-30°C
Explanation:
F-32/180 =C-0/100
or, -22-32/180=C/100
or, -54/180*100=C
or, -0.3*100=C
therefore, C= -30
-22°F = -30°C
PLEASE MARK ME AS BRAINLIEST!
It's the energy your body spends to just keep you breathing and your heart beating ... just being alive, without trying to DO anything.
Answers:(a) ![B_o = 0.3466](https://tex.z-dn.net/?f=B_o%20%20%3D%200.3466)
μT
(b) ![\lambda = 0.4488](https://tex.z-dn.net/?f=%5Clambda%20%3D%200.4488)
μm
(c) f =
Explanation:Given electric field(in y direction) equation:
![E_y = 104sin(1.40 * 10^7 x -\omega t)](https://tex.z-dn.net/?f=E_y%20%3D%20104sin%281.40%20%2A%2010%5E7%20x%20-%5Comega%20t%29)
(a) The amplitude of electric field is
![E_o = 104](https://tex.z-dn.net/?f=E_o%20%3D%20104)
. Hence
The amplitude of magnetic field oscillations is
![B_o = \frac{E_o}{c}](https://tex.z-dn.net/?f=B_o%20%3D%20%20%5Cfrac%7BE_o%7D%7Bc%7D%20)
Where c = speed of light
Therefore,
![B_o = \frac{104}{3*10^8} = 0.3466](https://tex.z-dn.net/?f=B_o%20%3D%20%20%5Cfrac%7B104%7D%7B3%2A10%5E8%7D%20%3D%200.3466)
μT (Where T is in seconds--signifies the oscillations)
(b) To find the wavelength use:
![\frac{2 \pi }{\lambda} = 1.40 * 10^7](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%20%5Cpi%20%7D%7B%5Clambda%7D%20%3D%201.40%20%2A%2010%5E7)
![\lambda = \frac{2 \pi}{1.40} * 10^{-7}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%20%5Cfrac%7B2%20%5Cpi%7D%7B1.40%7D%20%2A%2010%5E%7B-7%7D)
![\lambda = 0.4488](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%200.4488)
μm
(c) Since c = fλ
=> f = c/λ
Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f =
Answer:
500 watts
Explanation:
Recall that the definition of power is the amount of energy delivered per unit of time.
In our case, the energy delivered is potential energy which we can estimate as the product of the weight of the object times the distance it is lifted above ground:
200 N x 10 m = 2000 Nm
then the power is the quotient of this potential energy divided the time it took to lift the object to that position:
Power = 2000 / 4 Nm/s = 500 Nm/s = 500 watts