Gravity affects weight, it does not affect mass. Masses always remain the same. Newton's Second Law of Motion: Force = mass x acceleration The acceleration of an object is: a) directly proportional to the net force acting on the object. ... c) inversely proportional to the mass of the object.
Answer:
32500N
Explanation:
Data obtained from the question include:
m (mass) = 2500 kg
a (acceleration) = 13 m/s2
F (force) =?
Force is the product of mass and acceleration. It is represented mathematically as:
Force = mass x acceleration
F = m x a
With the above formula, the force with which the car strikes the barrier can be obtained as follow:
F = m x a
F = 2500 x 13
F = 32500N
Therefore, the car will strike the barrier with a force of 32500N
Answer:
The answer is 12.67 TMU
Explanation:
Recall that,
worker’s eyes travel distance must be = 20 in.
The perpendicular distance from her eyes to the line of travel is =24 in
What is the MTM-1 normal time in TMUs that should be allowed for the eye travel element = ?
Now,
We solve for the given problem.
Eye travel is = 15.2 * T/D
=15.2 * 20 in/24 in
so,
= 12.67 TMU
Therefore, the MTM -1 of normal time that should be allowed for the eye travel element is = 12.67 TMU
The age of the galaxy when we look back is 13.97 billion years.
The given parameters:
- <em>distance of the galaxy, x = 2,000 Mpc</em>
According Hubble's law the age of the universe is calculated as follows;
v = H₀x
where;
H₀ = 70 km/s/Mpc
![T = \frac{x}{V} \\\\T = \frac{x}{xH_0} \\\\T = \frac{1}{H_0} \\\\T = \frac{1}{70 \ km/s/Mpc} \\\\T = \frac{1 \ sec}{70 \times 3.24 \times 10^{-20} } \\\\T = 4.41 \times 10^{17} \ sec\\\\T = \frac{4.41 \times 10^{17} \ sec\ \times \ years}{3600 \ s \ \times\ 24\ h\ \times \ 365.25 \ days} \\\\T = 1.397 \times 10^{10} \ years\\\\T = 13.97 \ billion \ years](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7Bx%7D%7BV%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7Bx%7D%7BxH_0%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B1%7D%7BH_0%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B1%7D%7B70%20%5C%20km%2Fs%2FMpc%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B1%20%5C%20sec%7D%7B70%20%5Ctimes%203.24%20%5Ctimes%2010%5E%7B-20%7D%20%7D%20%5C%5C%5C%5CT%20%3D%204.41%20%5Ctimes%2010%5E%7B17%7D%20%5C%20sec%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B4.41%20%5Ctimes%2010%5E%7B17%7D%20%5C%20sec%5C%20%20%5Ctimes%20%5C%20years%7D%7B3600%20%5C%20s%20%5C%20%5Ctimes%5C%20%2024%5C%20h%5C%20%20%5Ctimes%20%5C%20365.25%20%5C%20days%7D%20%5C%5C%5C%5CT%20%3D%201.397%20%20%5Ctimes%2010%5E%7B10%7D%20%5C%20years%5C%5C%5C%5CT%20%3D%2013.97%20%5C%20billion%20%5C%20years)
Thus, the age of the galaxy when we look back is 13.97 billion years.
Learn more about Hubble's law here: brainly.com/question/19819028
Answer:
a) ![\Delta s=443037.9747\ J.K^{-1}](https://tex.z-dn.net/?f=%5CDelta%20s%3D443037.9747%5C%20J.K%5E%7B-1%7D)
b) ![\Delta s=31868131.8681\ J.K^{-1}](https://tex.z-dn.net/?f=%5CDelta%20s%3D31868131.8681%5C%20J.K%5E%7B-1%7D)
Explanation:
a)
Given:
amount of heat transfer occurred,![dQ=3.5\times 10^6\ J](https://tex.z-dn.net/?f=dQ%3D3.5%5Ctimes%2010%5E6%5C%20J)
initial temperature of car, ![T_i=36.5+273=309.5\ K](https://tex.z-dn.net/?f=T_i%3D36.5%2B273%3D309.5%5C%20K)
final temperature of car, ![T_f=44.4+273=317.4\ K](https://tex.z-dn.net/?f=T_f%3D44.4%2B273%3D317.4%5C%20K)
We know that the change in entropy is given by:
![\Delta s=\frac{dQ}{T_f-T_i}](https://tex.z-dn.net/?f=%5CDelta%20s%3D%5Cfrac%7BdQ%7D%7BT_f-T_i%7D)
(heat is transferred into the system of car)
![\Delta s=443037.9747\ J.K^{-1}](https://tex.z-dn.net/?f=%5CDelta%20s%3D443037.9747%5C%20J.K%5E%7B-1%7D)
b)
amount of heat transfer form the system of house,
initial temperature of house, ![T_i=23.5+273=296.5\ K](https://tex.z-dn.net/?f=T_i%3D23.5%2B273%3D296.5%5C%20K)
final temperature of house, ![T_f=5.3+273=278.3\ K](https://tex.z-dn.net/?f=T_f%3D5.3%2B273%3D278.3%5C%20K)
![\Delta s=\frac{dQ}{T_f-T_i}](https://tex.z-dn.net/?f=%5CDelta%20s%3D%5Cfrac%7BdQ%7D%7BT_f-T_i%7D)
![\Delta s=\frac{5.8\times 10^8}{278.3-296.5}](https://tex.z-dn.net/?f=%5CDelta%20s%3D%5Cfrac%7B5.8%5Ctimes%2010%5E8%7D%7B278.3-296.5%7D)
![\Delta s=31868131.8681\ J.K^{-1}](https://tex.z-dn.net/?f=%5CDelta%20s%3D31868131.8681%5C%20J.K%5E%7B-1%7D)