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TEA [102]
3 years ago
9

An elephant and a mouse would both have zero weight in gravity-free space. If they were moving toward you with the same speed, w

ould they bump into you with the same effect? Explain.
Physics
1 answer:
Dovator [93]3 years ago
8 0

The elephant and the mouse having zero weight in a gravity free space will not bump into you at the same effect.

<u>Explanation: </u>

When both are in a gravity free space, the weights are zero, as we know that the\text {weight of the body}=\text {mass of the body} \times \text {acceleration due to gravity}

\text {here, the weight of elephant}=\text {mass of elephant } \times \text {zero gravti} y=zero

\text {similarly,weight of mouse}=\text {mass of mouse } \times \text {zero gravity}=zero

But when they will acquire the speed of same magnitude, say v, their different masses will acquire different momentum, which will make the difference in effect while bumping.  

\text { momentum of elephant }=\text { mass of elephant } \times v  \text { momentum of mouse = mass of mouse } \times v

And as we know \text { mass of elephant }>\text { mass of mouse }  Therefore, effect of impact by elephant will be more than that of mouse . An elephant breaking into you will take you back faster than a mouse in space hits you.

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Katarina [22]

Answer:

400 Ns

Explanation:

Impulse = Change in momentum

i.e I = ΔP

So that,

Impulse experienced by Max = Change in Max's momentum

Change in Max's momentum = m(v - u)

Where m is the mass, v is the velocity after collision, and u is the velocity before collision.

m = 100.0 kg, v = 2.0 m/s, u = 6.0 m/s

Change in Max's momentum = 100 x (2 -6)

                             = -400 kg m/s

The negative sign shows that the change in momentum was against his direction of motion.

Impulse experienced by Max = 400 Ns.

Thus,

Max experienced an impulse of 400 Ns as a result of the collision.

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3 years ago
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3 years ago
The design of interior spaces is relatively unimportant to good<br> architecture?
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3 years ago
The average standard rectangular building brick has a mass of 3.10 kg and dimensions of 225 m x 112 m x 75 m. The gravitational
zzz [600]

Answer:

P=3.61\times 10^{-3}\ Pa

Explanation:

Given that,

Mass of a brick, m = 3.1 kg

The dimensions of the brick 225 m x 112 m x 75 m

We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :

P=\dfrac{F}{A}

F = mg

A = area with minimum dimensions i.e. 112 m x 75 m

Pressure is maximum when the area is least.

So,

P=\dfrac{mg}{A}\\\\P=\dfrac{3.1\times 9.8}{112\times 75}\\\\P=3.61\times 10^{-3}\ Pa

So, the maximum pressure created by brick is 3.61\times 10^{-3}\ Pa.

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3 years ago
Define the term potential energy of a body? <br> How is it measured
DENIUS [597]

Answer:

potential energy. noun. the energy of a body or system as a result of its position in an electric, magnetic, or gravitational field. It is measured in joules (SI units), electronvolts, ergs, etcSymbol: E p, V, U, φ Abbreviation: PE.

Explanation:

4 0
3 years ago
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