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TEA [102]
3 years ago
9

An elephant and a mouse would both have zero weight in gravity-free space. If they were moving toward you with the same speed, w

ould they bump into you with the same effect? Explain.
Physics
1 answer:
Dovator [93]3 years ago
8 0

The elephant and the mouse having zero weight in a gravity free space will not bump into you at the same effect.

<u>Explanation: </u>

When both are in a gravity free space, the weights are zero, as we know that the\text {weight of the body}=\text {mass of the body} \times \text {acceleration due to gravity}

\text {here, the weight of elephant}=\text {mass of elephant } \times \text {zero gravti} y=zero

\text {similarly,weight of mouse}=\text {mass of mouse } \times \text {zero gravity}=zero

But when they will acquire the speed of same magnitude, say v, their different masses will acquire different momentum, which will make the difference in effect while bumping.  

\text { momentum of elephant }=\text { mass of elephant } \times v  \text { momentum of mouse = mass of mouse } \times v

And as we know \text { mass of elephant }>\text { mass of mouse }  Therefore, effect of impact by elephant will be more than that of mouse . An elephant breaking into you will take you back faster than a mouse in space hits you.

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3 years ago
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A bullet is fired horizontally at a height of 1.3 meters and a velocity of 950 m/s. How long was the bullet in the air?
seropon [69]

Answer:

<em>The bullet was 0.52 seconds in the air.</em>

Explanation:

<u>Horizontal Motion </u>

It occurs when an object is thrown horizontally with a speed v from a height h.

The object describes a curved path ruled exclusively by gravity until it hits the ground.

To calculate the time the object takes to hit the ground, we use the following equation:

\displaystyle t=\sqrt{\frac{2y}{g}}

Note it doesn't depend on the initial velocity but on the height.

The bullet is fired horizontally at h=1.3 m, thus:

\displaystyle t=\sqrt{\frac{2\cdot 1.3}{9.8}}

\displaystyle t=\sqrt{\frac{2.6}{9.8}}

t = 0.52 s

The bullet was 0.52 seconds in the air.

3 0
2 years ago
For any molecule, formula unit, or ion, the sum of the average atomic masses of all the atoms represented in a formula is the.
alukav5142 [94]

The mass of a substance is given in atomic mass units and is calculated by adding the average atomic masses of all the atoms in the substance's chemical formula.

<h3>What empirical formula represents the total average atomic mass of every atom?</h3>

The Method The average atomic masses of all the atoms included in a formula's representation are added to get the mass of any molecule, formula unit, or ion. It has no bearing on the number of significant figures because the number of atoms is an exact quantity. One H2O molecule weighs 18.02 amu on average.

<h3>What connection exists between the empirical formula and the molecular formula?</h3>

You can determine the number of atoms of each element in a molecule using its molecular formula. These empirical formulations provide the most basic or reduced elemental ratio of a compound. The empirical formula and the molecular formula of a substance are same if the molecular formula can no longer be decreased.

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5 0
8 months ago
There are 3.3V passing through an orange power supply cable, and there are 0.025 ohms of resistance in the orange wire. How much
PIT_PIT [208]
P = V^2 / R.

So, 3.3^2 / 0.025 = 435.6W.

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P = V*I. Also, I = V/R.
Substituting V/R in for I in the 1st equation, you get P = V^2 / R.
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3 years ago
Which one of the following is described fully by its magnitude?
kompoz [17]
Energy (C) is fully described by its magnitude.
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The other four things on the list are all vectors.
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