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lisov135 [29]
3 years ago
7

HELpPPPPppp!!!!!! will mark brainless

Chemistry
1 answer:
ANTONII [103]3 years ago
6 0

Answer:

A

Explanation:

This is because in the graph shown line A has a quite greater impact of refraction than line B .

Hence, we can conclude that line A has the greater reaction at a faster rate.

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The burning of propane gas can be represented as a balanced chemical reaction as follows: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) Calcula
Snezhnost [94]

Answer: 20L of H2O

Explanation:

C3H8 + 5O2 → 3CO2 + 4H2O

Recall 1mole of a gas contains 22.4L at stp

5moles of O2 contains = 5 x 22.4 = 112L

4moles of H2O contains = 4 x 22.4 = 89.6L

From the equation,

112L of O2 produced 89.6L H2O

There for 25L of O2 will produce XL of H2O i.e

XL of H2O = (25 x 89.6)/112 = 20L

6 0
4 years ago
Which statement is true about a polyatomic ion?
nataly862011 [7]
The correct answer is that it is made of atoms that are covalently bonded together. Hope this helps.
4 0
4 years ago
Explain what a mole of copper (Cu) atoms and a mole of Sulfur Dioxide (SO2) molecules have in common.
evablogger [386]

Answer:

The amount of molecules → 6.02×10²³

Explanation:

Avogadro Number (NA) is the amount of particles that are contained in 1 mol of anything.

It does not matter the mass of compounds, or molecules, 1 mol has 6.02×10²³ particles, the same number for every compound.

1 mol of H₂O that weighs 18 grams has 6.02×10²³ molecules

1 mol of sucrose, that weighs 342 g has 6.02×10²³ molecules

Generally, the NA  is the number of atoms in 12 grams of the carbon-12 isotope.

6 0
3 years ago
A 500 gram cube of lead is heated from 25 °C to 75 °C. How much energy was required to heat the lead? The specific heat of lead
Ludmilka [50]

Answer:

The energy required is 3225 Joules.

Explanation:

Given,

mass of lead cube = 500 grams

T₁ = 25°C

T₂ = 75°C

specific heat of lead = 0.129 J/g°C

Energy required to heat the lead can be found by using the formula,

Q = (mass) (ΔT) (Cp)

Here, ΔT = T₂ - T₁ = 75 - 25 = 50

Substituting the values,

Q = (500)(50)(0.129)

Q = 3225 Joules.

Therefore, energy required is 3225 J.

3 0
4 years ago
Ten grams of a gas occupies 12.5 liters at a pressure of 42.0 cm Hg. What is the volume when the pressure has increased to 75.0
Fantom [35]
Based on the question, it is evident that the question is based on Boyle's Law which we will use to find the answer necessary.

Now, Boyle's Equation: P₁V₁ = P₂V₂

     V₂ = P₁V₁  ÷  P₂

∴   V₂  =  (12.5L × 42.0 cm · Hg) ÷ 75 cm · Hg

⇒  V₂  = 7 L
 
Thus, the <span>volume when the pressure has increased to 75.0 cm Hg is 7 Litres.</span>
8 0
3 years ago
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