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pochemuha
2 years ago
9

Q#5 Balance and list the coefficients from reactants to products.

Chemistry
2 answers:
skad [1K]2 years ago
8 0

A. 2Fe_2O_3(s) +3C(s) → 4Fe(s) + 3CO_2(g)

B. 2Al(s) + 3FeO(s) → Fe(s) + 3Al_2O_3(s)

C. 2Al(s) +3H_2SO_4(aq) → Al_2(SO_4)_3(aq) + 3H_2(g)

What is a balanced chemical equation?

An equation that has an equal number of atoms of each element on both sides of the equation is called a balanced chemical equation.

A. 2Fe_2O_3(s) +3C(s) → 4Fe(s) + 3CO_2(g)

B. 2Al(s) + 3FeO(s) → Fe(s) + 3Al_2O_3(s)

C. 2Al(s) +3H_2SO_4(aq) → Al_2(SO_4)_3(aq) + 3H_2(g)

Learn more about the balanced chemical equation here:

brainly.com/question/15052184

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nika2105 [10]2 years ago
4 0

A. 2\text{Fe}_{2}\text{O}_{3}+3\text{C} \longrightarrow 4\text{Fe} +3\text{CO}_{2}

B. 2\text{Al}+3\text{FeO} \longrightarrow \text{Al}_{2}\text{O}_{3}+3\text{Fe}

C. 2\text{Al}+3\text{H}_{2}\text{SO}_{4} \longrightarrow \text{Al}_{2}(\text{SO}_{4})_{3}+3\text{H}_{2}

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If the sample has a total mass of 5.76 g and contains 1.79 g k, what are the percentages of kbr and ki in the sample by mass
Luden [163]

The percentages of KBr and KI  in the sample by mass is 80.68 and 19.32 % respectively.

<h3>What is Molar Mass ?</h3>

Molar mass is defined as the mass contained in 1 mole of sample.

It is given that

the sample has a total mass of 5.76 g contains KBr and KI

and contains 1.79 gm of K is present

what is the percentage of KBr and KI in the sample

Molecular weight of K = 39

Molecular weight of Br = 79.9

Molecular weight of I = 126.9

In KBr the mass percentage of K is 39/(39+79.9) = 32.89%

In KI the mass percentage of K is 39/(39+126.9) = 23.5%

Let the mass of KBr present in the sample is x

K will be 0.3289 x

and let the mass of KI present be y

K will be 0.235y

x +y =5.76

0.3289x+0.235y = 1.79

0.0939y = 0.1045

y = 1.1125 gm

x = 5.76-1.1125

x = 4.6475 gm

% of KBr = (4.6475/5.76  )*100 = 80.68 %

% of KI = (1.1125/5.76) *100 = 19.32%

To know more about Molar Mass

brainly.com/question/12127540

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8 0
2 years ago
What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100g of the substance increases in te
Ierofanga [76]

Answer:

0.417 J/gºC

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature (ΔT). This can be obtained as follow:

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 70 – 10

Change in temperature (ΔT) = 60 °C

Finally, we shall determine the specific heat capacity of the substance as follow:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 100 × C × 60

2500 = 6000 × C

Divide both side by 6000

C = 2500 / 6000

C = 0.417 J/gºC

Therefore, the specific heat capacity of substance is 0.417 J/gºC

5 0
2 years ago
Is a cellphone made from renewable resources *
kobusy [5.1K]

Answer:

Mobiles are made from many non-renewable materials which have been extracted from the earth – such as: Metals. Plastics.

Explanation:

4 0
3 years ago
Read 2 more answers
A solution is made
Anna11 [10]

Answer:

99.3%

Explanation:

The percent by mass of the solute can be expressed as:

  • % mass = \frac{MassSolute}{MassSolute+MassSolvent} * 100%

And for this problem:

  • Mass of Solute = Mass of sodium lithium chloride = 29 g
  • Mass of Solvent = Mass of Water

So to calculate the percent by mass first we need to <u>calculate the mass of water</u>, to do so we use its<em> density</em> (1 g/L):

  • 202 mL is equal to (202/1000) 0.202 L.

Density water = mass water / volume

  • 1 g/L = mass water / 0.202 L
  • Mass water = 0.202 g

Now we have all the data required to <u>calculate the % mass:</u>

  • % mass = \frac{29g}{29g+0.202g} * 100 % = 99.3%
3 0
3 years ago
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Complete the following double replacement reactions <br> b. ZnCO3 + BaCl2
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