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2 years ago

Q#5 Balance and list the coefficients from reactants to products.

Chemistry

2 answers:

skad [1K]2 years ago

8 0

A. $2Fe_2O_3(s) +3C(s)$ → $4Fe(s) + 3CO_2(g)$

B. $2Al(s) + 3FeO(s)$ → $Fe(s) + 3Al_2O_3(s)$

C. $2Al(s) +3H_2SO_4(aq)$ → $Al_2(SO_4)_3(aq) + 3H_2(g)$

What is a balanced chemical equation?

An equation that has an equal number of atoms of each element on both sides of the equation is called a balanced chemical equation.

A. $2Fe_2O_3(s) +3C(s)$ → $4Fe(s) + 3CO_2(g)$

B. $2Al(s) + 3FeO(s)$ → $Fe(s) + 3Al_2O_3(s)$

C. $2Al(s) +3H_2SO_4(aq)$ → $Al_2(SO_4)_3(aq) + 3H_2(g)$

Learn more about the balanced chemical equation here:

brainly.com/question/15052184

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nika2105 [10]2 years ago

4 0

A. $2\text{Fe}_{2}\text{O}_{3}+3\text{C} \longrightarrow 4\text{Fe} +3\text{CO}_{2}$

B. $2\text{Al}+3\text{FeO} \longrightarrow \text{Al}_{2}\text{O}_{3}+3\text{Fe}$

C. $2\text{Al}+3\text{H}_{2}\text{SO}_{4} \longrightarrow \text{Al}_{2}(\text{SO}_{4})_{3}+3\text{H}_{2}$

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Identify which of the following two reactions you would expect to occur more rapidly: (1) addition of HBr to 2-methyl-2-pentene

arlik [135]

Answer:

(1) addition of HBr to 2-methyl-2-pentene

Explanation:

In this case, we will have the formation of a carbocation for each molecule. For molecule 1 we will have a tertiary carbocation and for molecule 2 we will have a secondary carbocation.

Therefore the most stable carbocation is the one produced by the 2-methyl-2-pentene. So, this molecule would react faster than 4-methyl-1-pentene. (See figure)

3 0

3 years ago

The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) +

Mnenie [13.5K]

Answer: (a) The solubility of CuCl in pure water is $1.1 \times 10^{-3} M$ .

(b) The solubility of CuCl in 0.1 M NaCl is $9.5 \times 10^{-3} M$ .

Explanation:

(a) Chemical equation for the given reaction in pure water is as follows.

$CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)$

Initial: 0 0

Change: +x +x

Equilibm: x x

$K_{sp} = 1.2 \times 10^{-6}$

And, equilibrium expression is as follows.

$K_{sp} = [Cu^{+}][Cl^{-}]$

$1.2 \times 10^{-6} = x \times x$

x = $1.1 \times 10^{-3} M$

Hence, the solubility of CuCl in pure water is $1.1 \times 10^{-3} M$ .

(b) When NaCl is 0.1 M,

$CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)$ , $K_{sp} = 1.2 \times 10^{-6}$

$Cu^{+}(aq) + 2Cl^{-}(aq) \rightleftharpoons CuCl_{2}(aq)$ , $K = 8.7 \times 10^{4}$

Net equation: $CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)$

$K' = K_{sp} \times K$

= 0.1044

So for, $CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)$

Initial: 0.1 0

Change: -x +x

Equilibm: 0.1 - x x

Now, the equilibrium expression is as follows.

K' = $\frac{CuCl_{2}}{Cl^{-}}$

0.1044 = $\frac{x}{0.1 - x}$

x = $9.5 \times 10^{-3} M$

Therefore, the solubility of CuCl in 0.1 M NaCl is $9.5 \times 10^{-3} M$ .

7 0

3 years ago

HELP PLEASE Explain why the elements of group 1 and 7 are quite reactive

Sauron [17]

Group 17 is the most readily reduced elements on the periodic table, meaning that they are so close to being a stable elements, only missing 1 electron to complete their valance electron shell. Thus they will essentially react with anything to get that last electron!

Group 1 elements are extremely reactive because they are the most readily oxidized, they are very close to reaching stability by giving up only 1 electron. Thus they will react with almost anything to give up their electron.

8 0

3 years ago

Given the balanced equation representing a reaction:

Vladimir79 [104]

Answer:

Option A. Addition

Explanation:

Unsaturated compounds under goes addition reaction to produce saturated compounds..

In the equation given above i.e

H2C=CH2 + F–F —> FCH2CH2F

we can see that the double in H2C=CH2 disappear by the reaction of F–F to produce FCH2CH2F which has no double. This simply indicates that the F–F was added to H2C=CH2. Hence, the reaction is called addition reaction.

4 0

3 years ago

Which statement is true regarding a hydrogen bond? It is weaker than dipole interaction forces. It is weaker than London dispers

Rom4ik [11]

I believe the answer is C: "It occurs when a hydrogen atom bonds with electropositive atoms."

4 0

2 years ago

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