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noname [10]
2 years ago
7

At 2525 °c, what is the hydroxide ion concentration, [oh−][oh−] , in an aqueous solution with a hydrogen ion concentration of [h

]=1. 5×10−6[h ]=1. 5×10−6 m?
Chemistry
1 answer:
tensa zangetsu [6.8K]2 years ago
8 0

The hydroxide ion concentration [OH-] in an aqueous solution is 6.66 x 10⁻⁹ M

Experimental measurements of the pKw of water at 25ºC yielded a result of 14.0. The same method used to determine the pKa of all other water-soluble compounds that can function as acids in aqueous solution can also be used to determine this value from the examination of thermodynamic or electrochemical data for these aqueous solutions.

Water has a pkw=14

So it can be represented as,

[H+] [OH-] = 1×10^-14

Given [H+] = 1. 5×10^−6

So, [OH-] = (1*10^-14) / ( 1.5*10^-6)

               = 6.66 x 10⁻⁹ M

To know more about Aqueous Solution refer:

brainly.com/question/19587902

#SPJ4

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Answer:

E 1: cyclohexene

Explanation:

This reaction is an example of the dehydration of cyclic alcohols. The reaction proceeds in the following steps;

1) The first step of the process is the protonation of the cyclohexanol by the acid. This now yields H2O^+ attached to the cyclohexane ring.

2) the water molecule, which a good leaving group now leaves yielding a carbocation. This now leaves a cyclohexane carbocation which is highly reactive.

3) A water molecule now abstracts a proton from the carbon adjacent to the carbocation leading to the formation of cyclohexene and the regeneration of the acid catalyst. This is an E1 mechanism because it proceeds via a carbocation intermediate and not a concerted transition state, hence the answer.

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3 years ago
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3 years ago
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Answer:

E_{ionization}=5.45\times 10^{-19}\ J

Explanation:

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For transitions:

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Thus,

\Delta E=2.18\times 10^{-18}(\frac{1}{2^2} - \dfrac{1}{{\infty}^2})\ J

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3 years ago
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