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Tanya [424]
3 years ago
7

A driver has three ways to get from one city to another. There is an 80 % chance of encountering atraffic jam given he is on rou

te A , a 60 % chance given he is on route B , and a 30 % chance given he is onroute C. Because of other factors, such as distance and speed limits , the driver uses route A 50 % of thetime and routes B and C each 25 % of the time. If the driver calls the dispatcher to inform him that he isin a traffic jam, find the probability that he selected route A
Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

The probability is 0.64

Step-by-step explanation:

What we want to calculate here is conditional probability.

Let P(A )= Probability of using route A = 50% = 0.5

Let P( B )= probability of using route B = 25% = 0.25

Let P (C )= probability of using route C = 25% = 0.25

Let T be the probability that he will be in a traffic Jam

The probability that he will be in a traffic Jam if he uses route A = 80%

Mathematically this is written as P( T | A) which is read as probability of T given A

so P( T | A) = 0.8

Same way for B and C which can be written as follows;

P( T | B) = 60% = 0.6

P( T | C) = 30% = 0.3

Now, what do we want to calculate?

He is in a traffic Jam, and we want to find the probability that he used route A. This means we want to find P(A) given T which can be written mathematically as P ( A | T)

We can find this using the other parameters and especially the equation below;

P ( A | T) = P(A) • P( T| A) / {P(A) • P ( T | A) + P(B)• P(T| B) + P(C) • P(T|C)

P( A | T) = (0.5 * 0.8)/ ( 0.5)(0.8) + (0.25)(0.6) + (0.25)(3) = 0.4/(0.4 + 0.75 + 0.075) = 0.4/0.625 = 0.64

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Step-by-step explanation:

we know that

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therefore work done is 2500Joule

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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
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Verdich [7]

Answer:

The % students going to higher education is 79.60 % which is higher than the reported value.

Step-by-step explanation:

According to national study report the students going to college for higher education = 75 %

Given that

156 of their 196 graduates last year went on to college.

% students going to higher education is

(\frac{156}{196}) 100 = 79.60

Thus the % students going to higher education is 79.60 % which is higher than the reported value.

4 0
3 years ago
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