An unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below.

Chemistry

1 answer:

charle [14.2K]3 years ago

6 0

Answer:

Explanation:

You have the unbalanced chemical reaction:

BF3 + Li2SO3 ⇒ B2(SO3)3 + LiF

Knowing that there are 2 atoms of boron in the products, we need to adjust that element putting 2 as coefficient of BF3.

2BF3 + Li2SO3 ⇒ B2(SO3)3 + LiF

Then, we need to balance fluor. There are 6 atoms of F in the reactants, for that reason, we write 6 in the lithium fluoride.

2BF3 + Li2SO3 ⇒ B2(SO3)3 + 6LiF

Finally, sulfur and oxygen have to be adjusted. 3 before lithium sulfite is enough to balance the chemical reaction.

2BF3 + 3Li2SO3 ⇒ B2(SO3)3 + 6LiF

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Vaselesa [24]

Answer: 1.6L

Explanation:

V1 = 1.50 L,

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3 years ago

Read 2 more answers

1. Mg2+ and Ca2+ are in the same group on the periodic table. In terms of electronic

finlep [7]

Answer:

Se detailed explanation.

Explanation:

Hello,

In this case, since both magnesium and calcium ions are in group IIA, we can review the following similar properties:

- Since both calcium and magnesium are in group IIA they have two valence electrons, it means that the both of them have two electrons at their outer shells.

- They are highly soluble in water when forming ionic bonds with nonmetals such as those belonging to halogens and oxygen's family.

- Calcium has 18 electrons and magnesium 10 which are two less than the total protons (20 and 12 respectively) since the both of them have lost two electrons due their ionized form.

- Their electron configurations are:

$Ca^{20}=1s^2,2s^2,2p^6,3s^3,3p^6,4s^2\\\\Mg^{12}=1s^2,2s^2,2p^6,3s^2$