Question

calculate the amount of hydrogen sulphide that would be liberated by the action of sulphuric acid on 4.4 gram of ferrous sulphide. (Fe=56;S=32)​

Answer 1

You will get iron sulfate and hydrogen sulfide gas (a.k.a. rotten egg gas).

FeS + H2SO4 = FeSO4 + H2S(g)

Change in Free Energy: ΔG(20C) = -66.6kJ (negative, so the reaction runs)

Change in Enthalpy: ΔH(20C) = -37.3kJ (negative, so the reaction is exothermic)