calculate the amount of hydrogen sulphide that would be liberated by the action of sulphuric acid on 4.4 gram of ferrous sulphid
e. (Fe=56;S=32)
1 answer:
You will get iron sulfate and hydrogen sulfide gas (a.k.a. rotten egg gas).
FeS + H2SO4 = FeSO4 + H2S(g)
Change in Free Energy: ΔG(20C) = -66.6kJ (negative, so the reaction runs)
Change in Enthalpy: ΔH(20C) = -37.3kJ (negative, so the reaction is exothermic)
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