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lys-0071 [83]
3 years ago
14

calculate the amount of hydrogen sulphide that would be liberated by the action of sulphuric acid on 4.4 gram of ferrous sulphid

e. (Fe=56;S=32)​
Chemistry
1 answer:
zaharov [31]3 years ago
7 0

You will get iron sulfate and hydrogen sulfide gas (a.k.a. rotten egg gas).

FeS + H2SO4 = FeSO4 + H2S(g)

Change in Free Energy: ΔG(20C) = -66.6kJ (negative, so the reaction runs)

Change in Enthalpy: ΔH(20C) = -37.3kJ (negative, so the reaction is exothermic)

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Answer:

Please find how these data prove the law of multiple proportions below

Explanation:

The law of multiple proportions was proposed by an English chemist called John Dalton. The law states that when two elements combine and to form more than one compound. The weights/masses of the second element in the two compounds, which combines with a fixed ratio of the first element, is in a simple whole number ratio.

In this question, Nitrogen is said to combine with oxygen to give three different compounds as follows:

A) laughing gas containing 63.65% nitrogen i.e. 0.6365g

This means that the mass of oxygen will be (1-0.6365) = 0.3635g

B) colorless gas containing 46.68% nitrogen i.e. 0.4668g

This means that the mass of oxygen will be 0.5332g

C) brown toxic gas containing 30.45% nitrogen i.e. 0.3045g

This means that the mass of oxygen will be 0.6955g

The ratios of oxygen in the three compounds is therefore:

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Divide this ratio by the smallest number (0.3635)

0.3635/0.3635 = 1

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Multiply this ratio by 2, we have:

2: 2.9 : 3.8

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This proves the law of multiple proportions that oxygen is in simple whole number ratio in the three different compounds.

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What are reasons standardizing conditions in which chemist describe matter?
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