A box of weight 50 N is at rest on a floor where the coefficient of static friction is 0.20. A rope is attached to the box and p
1 answer:
Answer:
The friction force that exerts by the floor on the box is 10 N.
Explanation:
Given that,
Weight of the box, W = 50 N
The coefficient of static friction is 0.2
A rope is attached to the box and pulled horizontally to the right. We need to find the friction force that exerts by the floor on the box. The direction of frictional force is in left side as we know that the frictional force acts in the opposite direction of motion. The force of friction is given by :
N is normal reaction, N = W = 50 N
So, the friction force that exerts by the floor on the box is 10 N.
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Answer:
Fnet = F√2
Fnet = kq²/r² √2
Explanation:
A exerts a force F on B, and C exerts an equal force F on B perpendicular to that. The net force can be found with Pythagorean theorem:
Fnet = √(F² + F²)
Fnet = F√2
The force between two charges particles is:
F = k q₁ q₂ / r²
where
k is Coulomb's constant, q₁ and q₂ are the charges, and r is the distance between the charges.
If we say the charge of each particle is q, then:
F = kq²/r²
Substituting:
Fnet = kq²/r² √2
Answer:
The current is halved
Explanation:
The relationship between the current and the resistance is given by Ohm's Law, as follows:
where,
V = Voltage
I = Current
R = Resistance
Therefore, if we double the resistance:
Hence the correct option is:
<u>The current is halved</u>