Question

A box of weight 50 N is at rest on a floor where the coefficient of static friction is 0.20. A rope is attached to the box and pulled horizontally to the right. What is the friction force that exerts by the floor on the box and which direction

Answer 1

Answer:

The friction force that exerts by the floor on the box is 10 N.        

Explanation:

Given that,

Weight of the box, W = 50 N

The coefficient of static friction is 0.2

A rope is attached to the box and pulled horizontally to the right. We need to find the friction force that exerts by the floor on the box. The direction of frictional force is in left side as we know that the frictional force acts in the opposite direction of motion. The force of friction is given by :

$F=\mu N$

N is normal reaction, N = W = 50 N

$F=0.2\times 50\\\\F=10\ N$

So, the friction force that exerts by the floor on the box is 10 N.