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Butoxors [25]
4 years ago
9

A box of weight 50 N is at rest on a floor where the coefficient of static friction is 0.20. A rope is attached to the box and p

ulled horizontally to the right. What is the friction force that exerts by the floor on the box and which direction
Physics
1 answer:
Bas_tet [7]4 years ago
5 0

Answer:

The friction force that exerts by the floor on the box is 10 N.        

Explanation:

Given that,

Weight of the box, W = 50 N

The coefficient of static friction is 0.2

A rope is attached to the box and pulled horizontally to the right. We need to find the friction force that exerts by the floor on the box. The direction of frictional force is in left side as we know that the frictional force acts in the opposite direction of motion. The force of friction is given by :

F=\mu N

N is normal reaction, N = W = 50 N

F=0.2\times 50\\\\F=10\ N

So, the friction force that exerts by the floor on the box is 10 N.

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an object has a mass of 50kg, a final height of 20m and an initial height of 8m. what is the amount of work done
Andrei [34K]

amount of work done is 5880 J

Given:

mass of object = 50kg

Final height = 20m

initial height = 8m

To Find:

amount of work done

Solution:

work is done when a force acts upon an object to cause a displacement. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

The work done by gravity is given by the formula,

W = mgh

W = 50 x 9.8 x ( 20-8)

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So the work done is 5880 J

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2 years ago
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tatyana61 [14]

Answer:

0.76

Explanation:

we are given:

radius (r) =5.7 m

speed (s) = 1 revolution in 5.5 seconds

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coefficient of friction (Uk) = ?

 we can get the minimum coefficient of friction from the equation below

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m x r x ω^{2} = Uk x m x g

r x ω^{2} = Uk x g

Uk = \frac{ r x ω^{2} }{g}

where ω (angular velocity) = \frac{2π}{time}

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Uk = \frac{ 5.7 x 1.14^{2} }{9.8} = 0.76

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plasma is a superheated liquid

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