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3 years ago

Why is the force of gravity less on the moon than on Earth

Physics

2 answers:

PolarNik [594]3 years ago

7 0

Answer:

The moon is farther away from the earths gravitational pull :)

Explanation:

ololo11 [35]3 years ago

6 0

Because of the moons location in orbit and it’s distance from earth there is less of a gravitational pull.

You might be interested in

The unit of length most suitable for measuring the thickness of a cell phone is a

Elis [28]

centimeter or millimeter.

Explanation:

The unit of length most suitable for measuring the thickness of a cell phone is centimeter or millimeter.

Length refers to how long a material is.

There are different units of length.
Smaller units that are microscopic are used to measure length dimensions that are very small
For example, nanometre is used to express microscopic length values.
Centimeters and millimeters are used for small dimensions that we can easily see.
Longer lengths can take the order of a yard, kilometer, miles e.t.c

Learn more:

Length brainly.com/question/13035995

#learnwithBrainly

8 0

4 years ago

A uniform electric ﬁeld exists in the region between two oppositely charged plane-parallel plates. An electron is released from

Zigmanuir [339]

Answer:

Explanation:

given S = distance from the first = 3.20cm = 0.032m, t = 1.30×10−8 s

q = 1.6 x 10_19C

using S = at^2/2

acceleration = 0.032 X 2 /(1.30×10−8)^2

a = 3.79 x 10^14m/s^2

From F = ma

F = qE

ma = qE

E = ma /q = 9.11 x 10^-31 x 3.79 x 10^14 / 1.6 x 10^-19

E = magnitude of this electric ﬁeld. = 2156.3N/C

b) Find the speed of the electron when it strikes the second plate ; V^2 = 2as

= 2 X 3.79 x 10^14 X 0.032

= 4.92 X 10^6m/s

5 0

3 years ago

14*3(36/2(1*3)/6<br><img src="https://tex.z-dn.net/?f=14%20%5Ctimes%203%2836%20%5Cdiv%202%281%20%5Ctimes%203%29%20%5Cdiv%206" id

GarryVolchara [31]

<h2>10.5</h2><h3>remember pemdas</h3>

parentheses
exponents <em>excluded for this problem</em>
multiplication
division
addition
subtraction

<h3>step 1. start with what is at the top of the list.</h3>

parentheses

<h3>step 2. do 1 times 3 since it comes before division, and is in parentheses.</h3>

1 × 3 = 3

<h3>step 3. find 36 divided by 2</h3>

36 ÷ 2 = 18

<h3>step 4. add the values together</h3>

18 + 3 = 21

<h3>step 5. find 14 times 3</h3>

14 × 3 = 42 <em>you can also do 7 × 6 and will get the same result because 7 is half of 14 and 3 is half of 6</em>

<h3>step 6. add what is outside the parentheses</h3>

21 + 42 = 63

<h3>step 7. divide by 6</h3>

63 ÷ 6 = 10.5 $-- >$ 10 remainder of 3 <em>remainder means left over</em>

<em />

7 0

2 years ago

An Airbus A350 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the

alexdok [17]

Answer:

t=67.7s

Explanation:

From this question we know that:

Vo = 6m/s

a = 1.8 m/s2

D = 1500m

And we also know that:

$X=V_{o}*t + \frac{a*t^{2}}{2}$ Replacing the known values:

$1500=6t+0.9*t^{2}$ Solving for t we get 2 possible answers:

t1 = -44.3s and t2 = 67.7s Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:

t = 67.7s

8 0

3 years ago

The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca

larisa86 [58]

Answer:

The value is $E_i = 1.5596 *10^{-18} \ J$

Explanation:

From the question we are told that

The wavelength is $\lambda = 48.2 nm = 48.2 *10^{- 9 }\ m$

The velocity is $v = 2.371*10^6 \ m/s$

The mass of electron is $m_e = 9.109*10^{-31} \ kg$

Generally the energy of the incident light is mathematically represented as

$E = \frac{h * c}{\lambda}$

Here c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

h is the Planck constant with value $h = 6.62607015 * 10^{-34 } J\cdot s$

$E = \frac{6.62607015 * 10^{-34 }* 3.0 *10^{8}}{48.2 *10^{- 9 }}$

=> $E = 4.12 *10^{-18} \ J$

Generally the kinetic energy is mathematically represented as

$E_k = \frac{1}{2} * m_e * v^2$

=> $E_k = \frac{1}{2} * 9.109*10^{-31} * (2.371*10^6 )^2$

=> $E_k = 2.56 *0^{-18} \ J$

Generally the ionization energy is mathematically represented as

$E_i = 4.12 *10^{-18} - 2.56 *0^{-18}$

=> $E_i = 1.5596 *10^{-18} \ J$

8 0

3 years ago