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Marianna [84]
2 years ago
11

The same amount of substance was added to four beakers of water. The treatments were placed in the chart.

Physics
1 answer:
vfiekz [6]2 years ago
5 0

Answer: Solution W and Y solution have more solubility than X and Z

Solutions are homogeneous mixtures of two or more components. By uniform mix we mean that its structure and properties are the same in the whole mix. Generally, the component which is present in the largest quantity is known as solvent. Solvent determines the physical condition in which the solution exists. In addition to the solvent, one or more component present in the solution is called solutes. In this unit we will only consider binary solutions (i.e., with two components)

The structure of the solution can be described by expressing its concentration. The latter can either be expressed qualitatively or quantitatively. For example, in qualitatively we can say that the solution is diluted (i.e., relatively small amounts of solubility) or it is concentrated (i.e., relatively rarely sighs). But in real life such details may be very confusing and thus require a quantitative description of the solution. There are several ways that we can quantitatively describe the concentration of solutions. (i) Mass Percentage (W / W): The mass percentage of a component of the solution is defined as: mass of the component = mass of the component in the solution = 100 Total mass of the solution .For example, if by mass A solution is described by 10% glucose in water, it means that 10 grams of glucose dissolved in 90 grams of water, resulting in 100 grams of solution. The concentration described by a large percentage of the population is usually used in industrial chemical applications. For example, the commercial bleaching solution contains 3.62 mass percentages of sodium hypochlorite in water. (ii) Volume Percentage (V / V): Volume Percentage is defined as: Total Volume of Component Volume 100 (component) Volume% of Component  

Explanation:

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Tanzania [10]

Answer:

The answer is a.

Explanation: Billions of years ago, there were lakes and rivers in the surface of mars because mars had a denser atmosphere and higher surface temperatures which allowed a vast amount of liquid water on the surface. Recently, most of the water on mars today exist as ice.

6 0
3 years ago
The rounded atomic mass of K is _______<br> K stands for _____ and has _____ valence electron(s).
netineya [11]

Answer:

Potassium

k = Potassium

Potassium Has 19 Electrons

the atomic mass is 39.0983

4 0
2 years ago
Read 2 more answers
21. An object is moving at 5 m/s and a height of 4 m. If the object has a mass of 5 kg what is
Stels [109]

Answer: 258.7 J

Explanation:

Velocity of object V=5m/s

Mass ; 5kg

Height; h=4m

Mechanical energy is equal to sum of kinetic and potential energy

E=K+Ep

Kinetic energy is calculeted using; K=m*V²/2

Potential energy is calculated using : Ep=m*G*h

-------------------------------------------------------------------------

V=5m/s

m=5kg

h=4m

E=K+Ep

E=m*V²/2+m*G*h

E=5kg*(5m/s)²/2+5kg*9.81m/s²*4m

E=62.5J+196.2J

E=258.7 J

6 0
3 years ago
select one popular music either OPM or from other countries that you like most. a.why you like this music/song? b.What is the me
Maurinko [17]

Answer:

my favourite song is hym to the sea. That song reminds me of the innocent people who lost their lives in titanic a century ago. If I was the writer of that song ,i would not change the title of that song because I can feel the sound of ocean when I listen to that song.

4 0
3 years ago
What is the approximate radius of the n = 1orbit of gold ( Z<br> =19 )?
Serjik [45]

Answer:

r=6.72\times 10^{-13}\ m

Explanation:

Let r is the radius of the n = 1 orbit of the gold. According to Bohr's model, the radius of orbit is given by :

r=\dfrac{n^2h^2\epsilon_o}{Z\pi me^2}

Where

n = number of orbit

h = Planck's constant

Z = atomic number (for gold, Z = 79)

m = mass of electron

e = charge on electron

r=\dfrac{(6.63\times 10^{-34})^2 \times 8.85\times 10^{-12}}{79\pi \times 9.1\times 10^{-31}\times (1.6\times 10^{-19})^2}

r=6.72\times 10^{-13}\ m

So, the radius of the n = 1 orbit of gold is 6.72\times 10^{-13}\ m. Hence, this is the required solution.

4 0
3 years ago
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