Q5: An ice skater moving at 12 m/s coasts
1 answer:
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Answer:
v=0.94 m/s
Explanation:
Given that
M= 5.67 kg
k= 150 N/m
m=1 kg
μ = 0.45
The maximum acceleration of upper block can be μ g.
a= μ g ( g = 10 m/s²)
The maximum acceleration of system will ω²X.
ω = natural frequency
X=maximum displacement
For top stop slipping
μ g =ω²X
We know for spring mass system natural frequency given as
By putting the values
ω = 4.47 rad/s
μ g =ω²X
By putting the values
0.45 x 10 = 4.47² X
X = 0.2 m
From energy conservation
150 x 0.2²=6.67 v²
v=0.94 m/s
This is the maximum speed of system.
Answer:
Explanation:
The path length difference = extra distance traveled
The destructive interference condition is:
where m =0,1, 2,3........
So, ←
⇒ λ = 2Δd = 2×10 = 20
The work done on the box by the applied force is zero.
The work done by the force of gravity is 75.95 J
The work done on the box by the normal force is 75.95 J.
<h3>The given parameters:</h3>- Mass of the box, m = 3.1 kg
- Distance moved by the box, d = 2.5 m
- Coefficient of friction, = 0.35
- Inclination of the force, θ = 30⁰
- Work is said to be done when the applied force moves an object to a certain distance
The work done on the box by the applied force is calculated as;
where;
a is the acceleration of the box
The acceleration of the box is zero since the box moved at a constant speed.
The work done by the force of gravity is calculated as follows;
The work done on the box by the normal force is calculated as follows;
Learn more about work done here: brainly.com/question/8119756