How many mg of metallic ions are in 1.0 mL of 0.10 M LINO3

Chemistry

1 answer:

Anton [14]2 years ago

8 0

Answer:

0.6941 mg

Explanation:

First we calculate how many LiNO₃ moles there are, using the given concentration and volume:

1.0 mL * 0.10 M = 0.10 mmol LiNO₃

As 1 mol of LiNO₃ contains 1 mol of Li, in the problem solution there are 0.10 mmol of Li (the only metallic ion present).

Now we convert Li milimoles into miligrams, using its atomic mass:

0.10 mmol Li * 6.941 mg/mmol = 0.6941 mg

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