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Snezhnost [94]
3 years ago
6

What orbital does the quantum numbers n=4 l=2 ml=2 describe

Chemistry
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

Orbital designation

for Principle Quantum number n=4, this is the shell number & corresponds to N shell, (shells are designated K,L,M,N)

for Angular Momentum number l=2, this is the orbital level corresponding to d, given that l can be any integer 0-(n-1), for( 0,1,2,3 )corresponds to (s, p, d, f)

The orbital designation is 4d

for Magnetic Quantum number ml, the suborbitals correspond to -l through l, (-2,-1,0, 1,2)

for ml=-1 the suborbital -1 in the 4d sub shell with electron spin state ms=-1/2

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Consider the following reaction where Kc = 1.29×10-2 at 600 K: COCl2 (g) CO (g) + Cl2 (g) A reaction mixture was found to contai
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Answer:

1. In order to reach equilibrium COCl₂(g) must be consumed.

B. False

2. In order to reach equilibrium Kc must increase.

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3. In order to reach equilibrium CO must be consumed.

A. True.

4. Qc is greater than Kc.

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5. The reaction is at equilibrium. No further reaction will occur.

B. False.

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Based on the reaction:

COCl₂(g) → CO (g) + Cl₂(g)

And Kc is defined as:

Kc = 1.29x10⁻² = [CO] [Cl₂] / [COCl₂]

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Replacing in Kc formula:

4.66×10⁻²M × 3.76×10⁻²M / 0.104M = 1.68x10⁻²

As the concentrations are not in equilibrium, 1.68x10⁻² is defined as the <em>reaction quotient, Qc</em>.

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2. In order to reach equilibrium Kc must increase.

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3. In order to reach equilibrium CO must be consumed.

A. True.

4. Qc is greater than Kc.

A. True

5. The reaction is at equilibrium. No further reaction will occur.

B. False. The reaction is in equilibrium when Qc = Kc

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