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Snezhnost [94]
2 years ago
6

What orbital does the quantum numbers n=4 l=2 ml=2 describe

Chemistry
1 answer:
Natasha2012 [34]2 years ago
6 0

Answer:

Orbital designation

for Principle Quantum number n=4, this is the shell number & corresponds to N shell, (shells are designated K,L,M,N)

for Angular Momentum number l=2, this is the orbital level corresponding to d, given that l can be any integer 0-(n-1), for( 0,1,2,3 )corresponds to (s, p, d, f)

The orbital designation is 4d

for Magnetic Quantum number ml, the suborbitals correspond to -l through l, (-2,-1,0, 1,2)

for ml=-1 the suborbital -1 in the 4d sub shell with electron spin state ms=-1/2

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What is the total number of hydrogen atoms in a molecule of heptyne?
Step2247 [10]

Answer:

12

Explanation:

alkyne formula is CnH2n-2

heptyne = 7

6 0
3 years ago
How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh?
Semenov [28]
Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
         ? g ------------------ 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g 

hope this helps!
3 0
3 years ago
Read 2 more answers
A student mixed a small amount of iron filings and sulphur powder in a dish. He could not
Temka [501]

Answer:

\huge \boxed{\mathrm{Carbon \ disulphide}}

Explanation:

Carbon disulphide is the liquid that can be used to separate iron fillings and sulphur powder.

When carbon disulphide is poured into the dish, the sulphur powder gets easily dissolved in the carbon disulfide. The iron fillings are left to settle on the bottom of the dish.

The iron fillings can get seperated through filtration. When the mixture of sulphur powder and carbon disulphide gets completely evaporated, the sulphur powder is left over.

7 0
2 years ago
Which kind of plate boundary created the Mid-Atlantic Ridge or the chain of volcanoes underneath Atlantic Ocean?
Natali [406]

Answer:

Divergent plate boundary

Explanation:

7 0
3 years ago
How many moles of oxygen are needed to react with 87 grams of aluminum
labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s)  + 3O₂(l)   → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

Moles of aluminium:

Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

                              Al         :         O₂

                               4          :         3

                               3.2       :         3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

5 0
2 years ago
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