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ipn [44]
3 years ago
6

What molecules can be made using hydrogen, carbon, and nitrogen?​

Chemistry
1 answer:
Yuki888 [10]3 years ago
8 0

Answer:

Ammonia

Explanation:

Ammonia is the simplest possible molecule made with nitrogen and hydrogen. Methane is the simplest possible molecule made of carbon and hydrogen. Methanol is like methane, but it also has one oxygen atom as well.

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1) All atoms are _____.
Katyanochek1 [597]

All atoms are of <u>neutral charge, with an equal amount of protons and electrons.</u>

6 0
3 years ago
Read 2 more answers
a 1.912 g samplw of calcium chloride is decomposed and found to contain 0.690 g of Ca and 1.222 g of Cl. Calculate the mass perc
adoni [48]

Answer:

36.09% is the mass percent composition of calcium in calcium chloride

Explanation:

Mass percent is defined as one hundred times the ratio between the mass of a compound (In this case, Calcium), and the total mass of the sample:

<em>Mass Percent = Mass compound / Total mass of the sample × 100</em>

<em />

Computing the values of the problem:

Mass Percent = 0.690g / 1.912g * 100

Mass percent =

<h3>36.09% is the mass percent composition of calcium in calcium chloride</h3>
8 0
3 years ago
Item 3
Artist 52 [7]

Answer:

Speed is measured over time.

Explanation:

7 0
3 years ago
Calculate the hydroxide ion concentration [OH-] for a solution with a pH of 6.10
nalin [4]

There are different formula you need to keep in mind when solving for [OH-]

Given that pH = 6.10

pH + pOH = 14

6.10 + pOH = 14

pOH = 7.9

[OH-] = 10^(-pOH)

[OH-] = 10^(-7.9)

[OH-] = 0.000000013

[OH-] = 1.3 x 10^-8


<h2><u>Answer: [OH-] = 1.3 x 10^-8</u></h2>
4 0
3 years ago
15.3 g of nano3 were dissolved in 100g of water in a calorimeter. The temperature of the water drops from 25.00°c to 21.56°c. Ca
Arturiano [62]

Answer:

0.259 kJ/mol ≅ 0.26 kJ/mol.

Explanation:

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = ??? J).

m is the mass of the ice (m = 100.0 g).

c is the specific heat of water (c of ice = 4.186 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 21.56°C - 25.0°C = -3.44°C).

<em>∵ Q = m.c.ΔT</em>

∴ Q = (100.0 g)(4.186 J/g.°C)(-3.44°C) = -1440 J = -1.44 kJ.

<em>∵ ΔH = Q/n</em>

n = mass/molar mass = (100.0 g)/(18.0 g/mol) = 5.556 mol.

∴ ΔH = (-1.44 kJ)/(5.556 mol) = 0.259 kJ/mol ≅ 0.26 kJ/mol.

3 0
3 years ago
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