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igor_vitrenko [27]
3 years ago
11

Can someone help me asap please​

Physics
1 answer:
Vesna [10]3 years ago
4 0

Answer:

<u>Resultant</u><u> </u><u>force</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u> </u><u>N</u>

Explanation:

Resolving vertically:

{ \sf{F_{y} = (8 \cos 30 \degree) + (12 \cos 30 \degree)   }} \\ { \sf{ \sum F_{y} = 17.3 \: newtons }}

Resolving horizontally:

{ \sf{F_{x} = (8 \sin 30 \degree) + (12 \sin 30 \degree)   }} \\ { \sf{ \sum F _{x}  = 10 \: newtons}}

Resultant force:

{ \boxed{ \bf{F =  \sqrt{ {F _{x} }^{2} +   {F _{y} }^{2} } }}} \\ { \sf{F =  \sqrt{ {17.3}^{2} +  {10}^{2}  } }} \\ { \sf{F =  \sqrt{399.29} }} \\ F = 19.98 \approx20  \: newtons

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Answer:

A, C and D

Explanation:

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                --------------------------------------------------------→

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