<h2><em>THERE WAS A TORNADO????????????</em></h2><h2><em></em></h2><h2><em>SAY WHAT?!</em></h2>
Answer:
The rod`s charge must be positive, because the gravity force is pointing downwards and the electrostatic force must be pointing upwards (in order to balance the gravity force)
The charge is q_2 = 1.667 times 10^(-7) C
Explanation:
F_e = F_g
where F_g = m g and F_e= (1/4 pi e_0)*(q_1*q_2)/d^2,
please see the file attached for more details.
m = mass of the person = 80 kg
M = mass of earth = 5.98 x 10²⁴ kg
R = radius of earth = 6.37 x 10⁶ m
h = height above the earth's surface = 1400 km = 1.4 x 10⁶ m
r₁ = initial distance of the person from the center of earth when on surface = R = 6.37 x 10⁶ m
r₂ = final distance of the person from the center of earth when at some height = R + h = 6.37 x 10⁶ + 1.4 x 10⁶ = 7.77 x 10⁶ m
F₁ = Gravitational force of earth on the person when at surface
Gravitational force of earth on the person when at surface is given as
F₁ = G M m/r₁² eq-1
F₂ = Gravitational force of earth on the person when at some height
Gravitational force of earth on the person when at some height is given as
F₂ = G M m/r₂² eq-2
dividing eq-1 by eq-2
F₁ /F₂ = (G M m/r₁² )/(G M m/r₂²)
F₁ /F₂ = r₂²/r₁²
inserting the values
F₁ /F₂ = (7.77 x 10⁶)²/(6.37 x 10⁶)²
F₁ /F₂ = 1.49
Answer:
530.5 Hz
Explanation:
Given :
C=0.75 micro
L=120 mH
Reactance capacitor can be determined by
=
where c =capacitor
= 
Reactance inductor can be determined by
As they are in series so ,
On solving these value we get
As we know that
f = 
=
530.5 Hz
Answer:
emitted intensity is 7.48 10⁸ 8 W / m²
Explanation:
To calculate this energy, let's start by using the win displacement law, and the Planck equation
λ T = 2,898 10-3 m K
E = h f
c = f λ
E = h c /λ
λ = hc / E
calculate
(h c / E) T = 2,898 10⁻³
T = 2,898 10⁻³ E / h c
E = 4 eV (1.6 10⁻¹⁹ J / 1eV) = 6.4 10⁻¹⁹ J
T = 2,898 10⁻³ 6.4 10⁻¹⁹ / (6,626 10⁻³⁴ 3 10⁸)
T = 18.54 10⁻²² / (19.878 10⁻²⁶)
T = 0.9331 10⁴ K
Having the temperature at which the emission occurs we can use Stefan's law
P = σ A e T⁴
The constant σ = 5.670 10⁻⁸ W / m² K⁴, e is the emissivity for a black body worth 1
P / A = 5,670 10⁻⁸ 1 (0.9331 10⁴)⁴
P / A = 7.48 10⁸ 8 W / m²
