All categories

3 years ago

Calculate the speed for a car that went a distance of 125 kilometers in 2 hours time.

Physics

1 answer:

Murljashka [212]3 years ago

7 0

S=125km
t=2h
v=s/t=125/2=62,5km/h
or 62,5/3,6=17,36m/s

You might be interested in

Why is wavelength the main limiting factor on limit of resolution in light microscopy?

s344n2d4d5 [400]

The resolution of a microscope is the smallest resolvable distance between two objects. It is defined as the shortest distance between two points on a specimen and the observer can still distinguish them.
The wavelength is a determining and limiting factor in the degree of resolution afforded by the microscope. The relationship between the wavelength and the resolution is:
Shorter wavelengths yield higher resolution and visa versa.

3 0

3 years ago

Dormancy helps plants survive freezing temperatures and lack of

Paraphin [41]

Dont be rude she's asking you that the question Ugh
Oh and the answer is Liquid water even though water is already liquid ok its just water okay

7 0

3 years ago

Read 2 more answers

. How far apart must two point charges of 75.0 nC (typical of static electricity) be to have a force of 1.00 N between them?

o-na [289]

Answer:

0.00712 m

Explanation:

Given:

Charge on first particle (q₁) = 75 nC = $75\times 10^{-9}\ C$

Charge on second particle (q₂) = 75 nC = $75\times 10^{-9}\ C$

Force (F) = 1.00 N

Separation (d) = ?

The magnitude of force is given by Coulomb's law which states that, the magnitude of force acting between two charged particles separated by a distance is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.

Therefore, the magnitude of force is given as:

$F=\dfrac{k|q_1||q_2|}{d^2}$

Where, $k=9\times 10^9\ N\cdot m^2/ C^2$ is the coulomb's constant.

Plug in the given values and solve for 'd'. This gives,

$1.00=\frac{9\times 10^9\times 75.0\times 10^{-9}\times 75.0\times 10^{-9} }{d^2}\\\\d^2=\frac{9\times 10^9\times 75.0\times 10^{-9}\times 75.0\times 10^{-9} }{1.00}\\\\d=\sqrt{\frac{9\times 10^9\times 75.0\times 10^{-9}\times 75.0\times 10^{-9} }{1.00}}\\\\d=0.00712\ m$

Therefore, the distance between the charges is 0.00712 m.

6 0

3 years ago

a bus travels 4 km due north and 3 km due west going from bus station a to bus station b. the magnitude of the bus displacement

ladessa [460]

Answer:

5km

Explanation:

Magnitude of displacement is found by getting the resultant. Resultant is same as the bypotenuse hence

$R=\sqrt {{x^{2}+y^{2}}$ where x is the displacement in west direction and y is displacement in North direction. Substituting x with 3km and y with 4 km then

$R=\sqrt {{3^{2}+4^{2}}=5km$

4 0

3 years ago

When a machine is used to perform a task, work output is always more than work input. please select the best answer from the cho

Maurinko [17]

Properly input current above 40 voltage or 100 for example elecrical fan machine is used to perform a task, work output is always more than work

5 0

3 years ago