1) The object slows down due to kinetic friction.
2) The coefficient of kinetic friction is higher on a carpet than on the bare floor, therefore the object would slow down quicker on the carpet
Answer:
The distance by the ball clear the crossbar is 1.15 m
Explanation:
Given that,
Distance = 44 m
Speed = 24 m/s
Angle = 31°
Height = 3.05 m
We need to calculate the horizontal velocity
Using formula of horizontal velocity

Put the value into the formula


We need to calculate the vertical velocity
Using formula of vertical velocity

Put the value into the formula


We need to calculate the time
Using formula of time

Put the value into the formula


We need to calculate the vertical height
Using equation of motion

Put the value into the formula


We need to calculate the distance by the ball clear the crossbar
Using formula for vertical distance

Put the value of h


Hence, The distance by the ball clear the crossbar is 1.15 m
Answer:
The distance traveled during its acceleration, d = 214.38 m
Explanation:
Given,
The object's acceleration, a = -6.8 m/s²
The initial speed of the object, u = 54 m/s
The final speed of the object, v = 0
The acceleration of the object is given by the formula,
a = (v - u) / t m/s²
∴ t = (v - u) / a
= (0 - 54) / (-6.8)
= 7.94 s
The average velocity of the object,
V = (54 + 0)/2
= 27 m/s
The displacement of the object,
d = V x t meter
= 27 x 7.94
= 214.38 m
Hence, the distance the object traveled during that acceleration is, a = 214.38 m
<u>Answer:</u>
The spinning of the earth around its own axis causes day and night.
<u>Explanation:</u>
Earth has two types of motions. It spins around its own axis causing day and night every 12 hours and completes a rotation in 23.93 hours that make a full day. The part of the earth that faces sunlight during spinning experiences day and the other part has night. It also rotates around the sun and completes one rotation in 365 days that makes a year.
Answer:
(a) The value of the ratio m₁/m₂ is 0.581
(b) the acceleration of the combined masses is 1.139 m/s²
Explanation:
Given;
The acceleration of force applied to M₁, a₁ = 3.10 m/s²
The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²
Let this force = F
According Newton's second law of motion;
F = ma
(a) the value of the ratio m₁/m₂
since the applied force is same in both cases, M₁a₁ = M₂a₂

(b) the acceleration of m₁ and m₂ combined as one object under the action force F
F = ma


Therefore, the acceleration of the combined masses is 1.139 m/s²