Write the net ionic equation for the reaction that occurs when equal volumes of 0.546 M aqueous acetylsalicylic acid (aspirin) a
1 answer:
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to figure out the required net ionic equation by firstly writing out the complete molecular equation between aspirin and sodium acetate:
Whereas acetic acid and sodium acetylsalicylate are formed. Now, we write the complete ionic equation whereby sodium acetate and sodium acetylsalicylate are ionized because they are salts yet neither aspirin nor acetic acid are ionized as they are weak acids:
Finally, for the net ionic equation we cancel out the sodium spectator ions to obtain:
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Complete Question
The complete question is shown on the first uploaded image
Answer:
a) Splitting pattern for Ha= 2+1 , Triplet
For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3
Splitting pattern for Hb and Hc= 3+1 , Quartet
For Proton Hd, number of non equivalent protons n= 0
Splitting pattern for Hd= 0+1 , Singlet
b) Splitting pattern for Ha= 2+1 , Triplet
For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3
Splitting pattern for Hb and Hc= 3+1 , Quartet
For Proton Hd, number of non equivalent protons n= 0
Splitting pattern for Hd= 0+1 , Singlet
c) The IUPAC name is Butan-2-ol
Explanation:
Considering the first question the rule used for prediction of splitting pattern is n+1 (Pascal's Triangle rule), where n is number of H atom on the adjacent carbon which are non equivalent.
According to that for molecule 1 as shown on the second uploaded image
For Proton Ha, number of non equivalent protons n= 2
Splitting pattern for Ha= 2+1 , Triplet
For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3
Splitting pattern for Hb and Hc= 3+1 , Quartet
For Proton Hd, number of non equivalent protons n= 0
Splitting pattern for Hd= 0+1 , Singlet
Considering the second question for Molecule 2 as shown on the third uploaded image
For Proton Ha, number of non equivalent protons n= 1
Splitting pattern for Ha= 1+1=2 , Doublet
For Proton Hb, number of non equivalent protons n= 3
Splitting pattern for Hb= 3+1=4 , Quartet
For Proton Hc, number of non equivalent protons n= 3
Splitting pattern for Hc= 3+1=4 , Quartet
For Proton Hd, number of non equivalent protons n= 1
Splitting pattern for Ha= 1+1=2 , Doublet
Considering the third question
The name of the given molecule is gotten according to longest carbon chain = 4 (Prefix 'Butan')
Functional group = -OH (Suffix 'ol') at C-2
The IUPAC name is Butan-2-ol
