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Ivanshal [37]
3 years ago
9

Which shows that energy is being transformed?

Physics
2 answers:
Trava [24]3 years ago
6 0

Answer:

A

Explanation:

I think it's A, sorry if I'm wrong

agasfer [191]3 years ago
5 0

Answer:

<h3>I think its (A)</h3>

Explanation:

correct me if im wrong

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A 2 kg ball of clay moving at 35 m/s strikes a 10 kg box initially at rest. What is the velocity of the box after the collision?
Ainat [17]

Answer:

V = 5.83 m/s

Explanation:

Given that,

Mass of a ball of a clay, m = 2 kg

Initial speed of the clay, u = 35 m/s

Mass of a box, m' = 10 kg

Initially, the box was at rest, u' = 0

We need to find the velocity of the box after the collision. Let V be the common speed. Using the conservation of momentum to find it.

mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{2\times 35+10\times 0}{2+10}\\\\V=5.83\ m/s

So, the velocity of the box after the collision is equal to 5.83 m/s.

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3 years ago
A young girl gives her toboggan a push of 4.0m/s uphill. It slides up the hill slowing down at an acceleration of 8.0m/s down. I
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It takes 30 seconds for the whole journey
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3 years ago
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3 0
4 years ago
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Moji listed the solids in order of hardness as graphite &lt; chalk &lt; quartz. His
LuckyWell [14K]

Answer:

D

Explanation:

Moji could've chosen hardness tests that were not reliable.

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3 years ago
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A vertical spring (spring constant =160 N/m) is mounted on the floor. A 0.340-kg block is placed on top of the spring and pushed
AleksandrR [38]

(a) 3.5 Hz

The angular frequency in a spring-mass system is given by

\omega=\sqrt{\frac{k}{m}}

where

k is the spring constant

m is the mass

Here in this problem we have

k = 160 N/m

m = 0.340 kg

So the angular frequency is

\omega=\sqrt{\frac{160 N/m}{0.340 kg}}=21.7 rad/s

And the frequency of the motion instead is given by:

f=\frac{\omega}{2\pi}=\frac{21.7 rad/s}{2\pi}=3.5 Hz

(b) 0.021 m

The block is oscillating up and down together with the upper end of the spring. The block will lose contact with the spring when the direction of motion of the spring changes: this occurs when the spring is at maximum displacement, so at

x = A

where A is the amplitude of the motion.

The maximum displacement is given by Hook's law:

F=kA

where

F is the force applied initially to the spring, so it is equal to the weight of the block:

F=mg=(0.340 kg)(9.81 m/s^2)=3.34 N

k = 160 N/m is the spring constant

Solving for A, we find

A=\frac{F}{k}=\frac{3.34 N}{160 N/m}=0.021 m

3 0
3 years ago
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