Average speed = (total distance covered) / (time to cover the distance)
total distance covered = (4km + 2km + 1km) = 7 km
time to cover the distance = (32min + 22min + 16min) = 70 min
Average speed = (7 km) / (70 min)
Average speed = 0.1 km/minute
The resultant displacement of the man is 109.77 km in the direction N60°E.
<h3>Displacement</h3>
Displacement is the distance travelled in a specified direction.
To calculate displacement, the straight line from starting point to end point of travel is taken and calculated.
<h3>Resultant displacement of the man </h3>
In the example above, a man walks 95 km, East, then 55 km, north.
The two distances form a right-angled triangle with two sides 95 and 55 units. The hypotenuse gives the resultant displacement, D.
Using Pythagoras rule:
D^2 = 95^2 + 55^2
D^2 = 12050
D = 109.77
Thus, the resultant displacement is 109.77 km
To calculate the direction:
Let the direction be y
y + x = 90°
tan x = 55/95
tanx x = 0.578
x = 30°
Then, y = 90 - 30
y = 60°
Therefore, the resultant displacement of the man is 109.77 km in the direction N60°E.
Learn more about displacement at: brainly.com/question/321442
<span>division of Earth's history into time units based largely on the types of life-forms that lived only during certain periods.</span>
Answer:
fb = 240.35 Hz
Explanation:
In order to calculate the beat frequency generated by the first modes of each, organ and tube, you use the following formulas for the fundamental frequencies.
Open tube:
(1)
vs: speed of sound = 343m/s
L: length of the open tube = 0.47328m
You replace in the equation (1):
Closed tube:

L': length of the closed tube = 0.702821m

Next, you use the following formula for the beat frequency:

The beat frequency generated by the first overtone pf the closed pipe and the fundamental of the open pipe is 240.35Hz
Answer:
He requires 1 gram of mass.
Explanation:
The density is defined as:
(1)
Where m is the mass and V is the volume.
Then, m can be isolated from equation 1 in order to determine the mass.
(2)
Hence, he requires 1 gram of mass.