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rjkz [21]
2 years ago
15

A party shop delivers helium-filled balloons to homes and businesses. The owners realize from experience that on hot summer days

they should inflate the balloons only three-quarters full. On cold winter days they can fully inflate the balloons. Which of the following is the BEST hypothesis to explain this observation? Air outside the balloons leaks into the balloons. The helium gas is more active in the winter season. As the temperature increases, the helium in the balloons expands. Outdoor air pressure in the summer is less than indoor air pressure.
Physics
2 answers:
kvasek [131]2 years ago
6 0

Answer:As the temperature increases, the helium in the ballon expands.

Explanation:

I took the quiz already

worty [1.4K]2 years ago
5 0

The answer is C) As the temperature increases, the helium in the balloons expands.

Have a blessed day!

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With a velocity of 15 m/s, how long would it take the dog to run 100 meters?
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Answer

6.66 seconds imma seem like an idiot if something like this is werong

Explanation:

dogg is speed

100/15

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Which style of painting is the Peale family known for?
Misha Larkins [42]

The correct answer is option B, representational

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8 0
3 years ago
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A wire, 1.0 m long, with a mass of 90 g, is under tension. A transverse wave is propagated on the wire, for which the frequency
Mice21 [21]

Answer:

T = 712.9 N

Explanation:

First, we will find the speed of the wave:

v = fλ

where,

v = speed of the wave = ?

f = frequency = 890 Hz

λ = wavelength = 0.1 m

Therefore,

v = (890 Hz)(0.1 m)

v = 89 m/s

Now, we will find the linear mass density of the wire:

\mu = \frac{m}{L}

where,

μ = linear mass density of wie = ?

m = mass of wire = 90 g = 0.09 kg

L = length of wire = 1 m

Therefore,

\mu = \frac{0.09\ kg}{1\ m}

μ = 0.09 kg/m

Now, the tension in wire (T) will be:

T = μv² = (0.09 kg/m)(89 m/s)²

<u>T = 712.9 N</u>

7 0
2 years ago
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algol [13]

Answer:

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5 0
2 years ago
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A constant force of 12N is applied for 3.0s to a body initially at rest. The final velocity of the body is 6.0ms–1. What is the
sp2606 [1]
From the question,
u = 0m {s}^{ - 1}
v = 6m {s}^{ - 1}

t = 3s
F=12N



Using Impulse, the product of the constant force, F and time t equals the product of the mass of the body and change in velocity.

Ft =m(v-u)


12(3.0)=m(6.0- \: 0)
This implies that

36.0 = 6m
m =  \frac{36.0}{6.0}
\therefore \: m = 6.0kg


You can also use the equation of linear motion,
v = u + at
6 = 0 + a(3)
6 = 3a
a =  \frac{6}{3}

a = 2 {ms}^{ - 2}
But
F=ma
12 = m(2)
12 = 2m
\frac{12}{2}  = m
\therefore \: m = 6kg
4 0
3 years ago
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