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Ne4ueva [31]
2 years ago
15

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Mathematics
1 answer:
solniwko [45]2 years ago
5 0

Answer:

whow this is so great app i love it

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HELP ASAP ILL MARK U BRAINLIEST
prohojiy [21]

Answer: 300x200

Step-by-step explanation: First of all...Your perimeter equals 2x+3y. X=length, y=width.

2x+3y=1200

3y=1200-2x

y=400-(2/3)x

y=400-(2/3)x

Your Area = xy=x(400-2x/3)=400x-2^2/3

dA/dx=400-4x/3=0

4x/3=400

4x=1200

x=300ft length

y=400-(2/3)(300)=200ft

I hope this helps you!

3 0
3 years ago
What is the age of Alps mountain​
DIA [1.3K]

Step-by-step explanation:

The Alps were born 770 million years ago.

Hope this helps..

5 0
3 years ago
Read 2 more answers
A straight line has equation 3y-3x=4. Write down the equation of another straight line parallel to it
Sophie [7]
Y = 3x + 4/3
............
8 0
3 years ago
Find an equation of the sphere with center (4, −12, 8) and radius 10. use an equation to describe its intersection with each of
xxMikexx [17]
<span>Sphere: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 Intersection in xy-plane: (x - 4)^2 + (y + 12)^2 = 36 Intersection in xz-plane: DNE Intersection in yz-plane: (y + 12)^2 + (z - 8)^2 = 84 The desired equation is quite simple. Let's first create an equation for the sphere centered at the origin: x^2 + y^2 + z^2 = 10^2 Now let's translate that sphere to the desired center (4, -12, 8). To do that, just subtract the center coordinate from the x, y, and z variables. So (x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 10^2 (x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 100 Might as well deal with that double negative for y, so (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 And we have the desired equation. Now for dealing with the coordinate planes. Basically, for each coordinate plane, simply set the coordinate value to 0 for the axis that's not in the desired plane. So for the xy-plane, set the z value to 0 and simplify. So let's do that for each plane: xy-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + (y + 12)^2 + (0 - 8)^2 = 100 (x - 4)^2 + (y + 12)^2 + (-8)^2 = 100 (x - 4)^2 + (y + 12)^2 + 64 = 100 (x - 4)^2 + (y + 12)^2 = 36 xz-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + (0 + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + 12^2 + (z - 8)^2 = 100 (x - 4)^2 + 144 + (z - 8)^2 = 100 (x - 4)^2 + (z - 8)^2 = -44 And since there's no possible way to ever get a sum of 2 squares to be equal to a negative number, the answer to this intersection is DNE. This shouldn't be a surprise since the center point is 12 units from this plane and the sphere has a radius of only 10 units. yz-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (0 - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (-4)^2 + (y + 12)^2 + (z - 8)^2 = 100 16 + (y + 12)^2 + (z - 8)^2 = 100 (y + 12)^2 + (z - 8)^2 = 84</span>
6 0
3 years ago
A square pyramid has a base length of 6 inches. The height of each triangular face is 11 inches. Which expressions correctly cal
VMariaS [17]

Answer:

168 in²

Step-by-step explanation:

The square would be 36 in²

Area of a triangle is A= 1/2 bh

A = 1/2 (11 x 6), A= 1/2 (66)

1/2 (66) = 33 in², which is the area of a triangle.

Then you multiply 33 x 4 to get the area of all the triangles, which is 132 in²

You add the area of the square to the area of the triangles, which is 168 in².

7 0
3 years ago
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