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3 years ago

B. A redox reaction occurs in an electrochemical cell, where silver (Ag) is oxidized and nickel (Ni)

Chemistry

1 answer:

astra-53 [7]3 years ago

5 0

Answer:

See explanation

Explanation:

i) Oxidation half-reaction:

2Ag(s) ----> 2Ag^+(aq) + 2e

Reduction half-reaction:

Ni^2+(aq) + 2e ----> Ni(s)

ii) Ag is the anode while Ni is the cathode

iii) E°cell = E°cathode - E°anode

E°cell = (-0.25) - (0.80)

E°cell = -1.05 V

iv) This is an electrolytic cell since the cell reaction is non spontaneous.

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$n_1M_1V_1=n_2M_2V_2$

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$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.05M\\V_1=16mL\\n_2=2\\M_2=?M\\V_2=36.0mL$

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Putting values in above equation, we get:

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Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

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