The mass of chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.
The mass of chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.
The given parameters;
- <em>mass of the sodium chloride, = 14.5 g</em>
- <em>2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)</em>
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In the reaction above, we can deduce the following;
molecular mass of 2Nacl = 2(58.44) = 116.88 g
molecular mass of 2NaF = 2(42) = 84 g
molecular mass of Cl2 = 71 g
The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 84 g of NaF
14.5 g of NaCl ------------------- ?
The mass of chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 71 g of Cl2
14.5 g of NaCl ------------------- ?
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Answer:
See explanation below
Explanation:
In this case, we need to see which is the structure of this compound. Now, racemization occurs basically because we are in an aqueous basic medium, and the ketone can reacts again with water in the medium to form the starting reagent.
First, the base will take out the Alpha hydrogen from the ketone, then, the negative charge goes down and opens up the carbonile group, forming a double bond in there. Later, with the water of the medium, it reacts and substract a proton, and then, with keto enolic equilibrium, forms again the ketone, but this ketone is different from the start, it will be the R isomer which is not optically active.
See picture below for mechanism
Answer:
Explanation:
Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations. Only the species which are present in aqueous state dissociate. So, the net ionic equation of aqueous solution of ammonia is shown below as:-
B............................................................................
Answer:
Specific heat of alloy = 0.2 j/ g.°C
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of bold = 25 g
Heat absorbed = 250 J
Initial Temperature = 25°C
Final temperature = 78°C
Specific heat of alloy = ?
Solution:
Change in temperature:
ΔT = 78°C - 25°C
ΔT = 53°C
Now we will put the values in formula.
Q = m.c. ΔT
250 j = 25 g × c ×53°C
250 j = 1325 g.°C × c
250 j / 1325 g.°C = c
c = 0.2 j/ g.°C
