I think you meant K as in kilograms?
If so, the answer should be 0.0052.
88.98 %
The Balance Chemical Equation is as follow,
2 HCl + Pb(NO₃)₂ → 2 HNO₃ + PbCl₂
According to equation,
331.2 g (1 mole) Pb(NO₃)₂ produces = 278.1 g (1 mole) PbCl₂
So,
870 g of Pb(NO₃)₂ will produce = X g of PbCl₂
Solving for X,
X = (870 g × 278.1 g) ÷ 331.2 g
X = 730.5 g of PbCl₂
Therefore,
Theoretical Yield = 730.5 g
Also as given,
Actual Yield = 650 g
So using following formula for percentage yield,
%age Yield = (Actual Yield / Theoretical Yield) × 100
Putting values,
%age Yield = (650 g / 730.5 g) × 100
%age Yield = 88.98 %
Brianliest please and thank you.
Answer:
13.36
first you have to convert the grams of nitrogen into moles when you got the moles of nitrogen. Then 2 moles of ammonia react with 1 mole nitrogen you have doubled the nitrogen mole and then convert the moles into the grams of ammonia.
use this formula for that:
moles = gram/molar mass
The given compound is ![K_{2}Cr_{2}O_{7}](https://tex.z-dn.net/?f=%20K_%7B2%7DCr_%7B2%7DO_%7B7%7D%20%20%20%20)
Each formula unit of
has 2 mol Potassium (K) atoms, 2 mol Chromium (Cr) atoms and 7 mol Oxygen (O) atoms.
Atomic weight of potassium is 39.0983 amu
Atomic weight of Chromium is 51.9961 amu
Atomic weight of Oxygen is 15.9994 amu.
Therefore the formula weight of ![K_{2}Cr_{2}O_{7} =](https://tex.z-dn.net/?f=%20K_%7B2%7DCr_%7B2%7DO_%7B7%7D%20%3D%20%20%20%20%20)
![2 * 39.0983 amu + 2 * 51.9961 amu + 7 * 15.9994 amu](https://tex.z-dn.net/?f=%202%20%2A%2039.0983%20amu%20%2B%202%20%2A%2051.9961%20amu%20%2B%207%20%2A%2015.9994%20amu%20)
= 294.1846 amu