The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
Learn more about minutes of distance apart here
brainly.com/question/8783264
A) m=-3
B) n=-17
hope this helps x
would love to have brainliest if it is right :)
A light-year is defined as the distance the light can cover in one year.
The light travels at speed of
, and one year converted into seconds is
So the distance covered by the light in one year is
And this is the distance that corresponds to one light-year.
Answer:
Pretty sure that it is False
Step-by-step explanation:
Sampling variation, random samples dont really reflect the population from where i is drawn, but it is close.
Answer:
40 grams of 13% alcohol solution and 10 grams of 18% alcohol solution.
Step-by-step explanation:
13%(x) + 18%(50-x) = 14%*50g Multiply them all
0.13x + (9-0.18x) = 7
0.13x-0.18x + 9 = 7 Simplify the equation and subtract 0.13x from 0.18x
9-0.05x = 7 Add 0.05x to each side
9 = 7+0.05x Subtract 7 from both sides
0.05x = 2 Multiply each side by 100
5x = 200 Divide both sides by 5
x = 40
50 - 40 = 10
40 grams and 10 grams
Your welcome