Question

What is the pressure of 1.20 moles of SO2 gas in a 4L container at 30 degrees celsius

Answer 1

Let suppose the Gas is acting Ideally, Then According to Ideal Gas Equation,

                                       P V  =  n R T
Solving for P,
                                       P  =  n R T / V     ----- (1)
Data Given;

Moles  = n = 1.20 mol

Volume  = V =  4 L

Temperature  = T = 30 + 273 = 303 K

Gas Constant  = R = 0.08206 atm.L.mol⁻¹.K⁻¹

Putting Values in Eq.1,

                     P  =  (1.20 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 303 K) ÷ 4 L

                     P  =  7.45 atm

Answer 2

Answer:

7.45 atm

Explanation:

Let suppose the Gas is acting Ideally, Then According to Ideal Gas Equation,

                                      P V  =  n R T

Solving for P,

                                      P  =  n R T / V     ----- (1)

Data Given;

Moles  = n = 1.20 mol

Volume  = V =  4 L

Temperature  = T = 30 + 273 = 303 K

Gas Constant  = R = 0.08206 atm.L.mol⁻¹.K⁻¹

Putting Values in Eq.1,

                    P  =  (1.20 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 303 K) ÷ 4 L

                    P  =  7.45 atm