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3 years ago

If you have a negative ion, what happened to the outer shell of the atom?

Chemistry

1 answer:

Nastasia [14]3 years ago

8 0

It will lose them and become stable

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How many moles are in 2.31*10^21 atoms of lead

Anon25 [30]

Hey there!:

Molar mass Lead ( Pb ) = 207.2 g/mol

Therefore:

1 mole Pb --------------------- 6.02*10²³ atoms
? moles Pb -------------------- 2.31*10²¹ atoms

moles Pb = ( 2.31*10²¹ ) * 1 / ( 6.02*10²³ ) =

moles Pb = ( 2.31*10²¹ ) / ( 6.02*10²³ ) =

=> 0.00383 moles of Pb

Hope this helps !

6 0

3 years ago

Salt crystals are shaped like cubes. Salt is part of the _____. isometric crystal system monoclinic crystal system hexagonal cry

sweet [91]

Salt crystals are shaped like cubes. Salt is part of the isometric crystal system.

6 0

3 years ago

Read 2 more answers

Enter the atomic symbol, including mass number and atomic number, for iodine-125.

ICE Princess25 [194]

Answer:

Explanation:

Iodine - 125

The atomic symbol of iodine is ¹²⁵₅₃ I

The symbol for iodine is I

The atomic number of iodine is 53,

and the atomic mass of iodine is 125 .

<u>The representation of the atomic symbol is as, the atomic mass is written in uppercase and the atomic number is written in lower case , followed by the symbol of the element .</u>

Iodine is a radio active element , used for many biological process .

It is the second largest -lived radioisotope of iodine .

The first is iodine-129 .

3 0

3 years ago

Gold has a density of 19.32 is this a chemical change or physical change

forsale [732]

Answer:

chemical change it is melted down

7 0

3 years ago

How many moles of Al would be produced from 20 moles of Al2O3?<br> 2Al2O3<br> -><br> 4A1 + 302

Evgesh-ka [11]

<h3>Answer:</h3>

$\displaystyle 40 \ mol \ Al$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 40 \ mol \ Al$

<u>Step 4:Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

4 0

3 years ago