The density of an object is calculated as Density = . If 100mL of water weighs 100g calculate the density?

You have an aqueous solution of chromium(III) nitrate that you titrate with an aqueous solution of sodium hydroxide. After a cer

barxatty [35]

Answer:

The precipitate was chromium hydroxide, which then reacted with more hydroxide to produce a soluble complex, Cr(OH)4

Explanation:

The following reaction takes place when chromium(III) nitrate reacts with NaOH:

$Cr(NO)_{3}$ +3 NaOH → $Cr(OH)_{3}$ (s)+ $NaNO_{3}$

The precipitate that is formed is chromium hydroxide, $Cr(OH)_{3}$

When more NaOH is added, the precipitate reacts with it which then results in the formation of a soluble complex ion:

$Cr(OH)_{3}$ (s) + $OH^{-}$ (aq) → $Cr(OH)_{4} ^{-}$ (aq)

$Cr(OH)_{4} ^{-}$ is soluble complex ion

7 0

3 years ago

Americans spend up to $100 billion annually for bottled water (41 billion gallons). The only beverages with higher sales are car

grigory [225]

Answer: C) be hypertonic to Tank B.

Explanation:

The ability of an extracellular solution to move water in or out of a cell by osmosis is known as its tonicity. Additionally, the tonicity of a solution is related to its osmolarity, which is the total concentration of all the solutes in the solution.

Three terms (hypothonic, isotonic and hypertonic) are used to compare the osmolarity of a solution with respect to the osmolarity of the liquid that is found after the membrane. When we use these terms, we only take into account solutes that can not cross the membrane, which in this case are minerals.

If the liquid in tank A has a lower osmolarity (lower concentration of solute) than the liquid in tank B, the liquid in tank A would be hypotonic with respect to the latter.
If the liquid in tank A has a greater osmolarity (higher concentration of solute) than the liquid in tank B, the liquid in tank A would be hypertonic with respect to the latter.
If the liquid in tank A has the same osmolarity (equal concentration of solute) as the liquid in tank B, the liquid in tank A would be isotonic with respect to the latter.

In the case of the problem, option A is impossible because the minerals can not cross the membrane, since it is permeable to water only. There is no way that the concentration of minerals decreases in tank A, so the solution in this tank can not be hypotonic with respect to the one in Tank B.

Equally, both solutions can not be isotonic and neither we can say that the solution in tank A has more minerals that the one in tank B because the liquid present in tank B is purified water that should not have minerals. Therefore, options B and D are also not correct.

Finally, the correct option is C, since in the purification procedure the water is extracted from the solution in tank A to obtain a greater quantity of purified water in tank B. In this way, the solution in Tank A would be hypertonic to Tank B.

5 0

3 years ago

What does solubility mean?

jasenka [17]

Answer: the ability to be dissolved, especially in water.

Explanation: I think the answer you've picked is right

Hope this helps

8 0

3 years ago

To answer this question, you will need to write the balanced equation and set up a BCA table. Using appropriate rounding rules,

Elenna [48]

Water decomposes when electrolyzed to produce hydrogen and oxygen gas. If 2.5 grams of water were decomposed 1.04 grams of oxygen will be formed.