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Maslowich
3 years ago
6

Which of the following statements applies to a nuclear fission reaction?

Chemistry
1 answer:
wlad13 [49]3 years ago
4 0

Answer:

d-the reaction released large amounts of energy when nuclei split apart

Explanation:

no explain

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When a bullet is fired from a gun what is true about the momentum
Eduardwww [97]

Before the bullet is fired the momentum is Zero because nothing is moving but once the bullet is shot the momentum increases because of the movement of the bullet moving forward.

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3 years ago
What temperature in celsius is 563.18 K
OleMash [197]

Answer:

Explanation: So 1 Kelvin is equal to -272.15 Celsius. Now we need to do some math,

563,180 x -272.15 = -153,269,437 Celsius

I hope this helps :)

6 0
3 years ago
a mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed
Dafna11 [192]

A mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed by the help of concentric hydrochloric acid.

<h3>What is concentric hydrochloric acid?</h3>

The concentric hydrochloric acid is used for the analysis of organic and inorganic mixture like  lithium chloride, lithium carbonate, and lithium nitrate it releases fumes and cannot be touched with normal hands.

Always use a dropper to use it and for the chemical analysis.

Therefore, mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed by the help of concentric hydrochloric acid.

Learn more about concentric hydrochloric acid, here,

brainly.com/question/24586675

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6 0
1 year ago
Acetylene gas, C2H2, can be produced by the reaction of calcium carbide and water. CaC2(s) + 2H2O(l) --&gt; C2H2(g) + Ca(OH)2(aq
nekit [7.7K]

Answer:

1.0 L

Explanation:

Given that:-

Mass of CaC_2 = 2.54\ g

Molar mass of CaC_2 = 64.099 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{2.54\ g}{64.099\ g/mol}

Moles_{CaC_2}= 0.0396\ mol

According to the given reaction:-

CaC_2_{(s)} + 2H_2O_{(l)}\rightarrow C_2H_2_{(g)} + Ca(OH)_2_{(aq)}

1 mole of CaC_2 on reaction forms 1 mole of C_2H_2

0.0396 mole of CaC_2 on reaction forms 0.0396 mole of C_2H_2

Moles of C_2H_2 = 0.0396 moles

Considering ideal gas equation as:-

PV=nRT

where,

P = pressure of the gas = 742 mmHg  

V = Volume of the gas = ?

T = Temperature of the gas = 26^oC=[26+273]K=299K

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles = 0.0396 moles

Putting values in above equation, we get:

742mmHg\times V=0.0396 mole\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 299K\\\\V=\frac{0.0396\times 62.3637\times 299}{742}\ L=1.0\ L

<u>1.0 L of acetylene  can be produced from 2.54 g CaC_2.</u>

4 0
3 years ago
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