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Maslowich
2 years ago
6

Which of the following statements applies to a nuclear fission reaction?

Chemistry
1 answer:
wlad13 [49]2 years ago
4 0

Answer:

d-the reaction released large amounts of energy when nuclei split apart

Explanation:

no explain

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What is an example of how enginers contrbiuted to society
SpyIntel [72]

Answer:

Engineers changed the world, such as building houses, bridges, and cars.

Please rate it the brainlist if this helped you and let me know if you have any questions, thanks

8 0
3 years ago
If oxygen has a molar mass of 16.0 g/mole, carbon has a molar mass of 12.0 g/mole and hydrogen has a molar mass of 1.01 g/mole,
Stolb23 [73]
The number of mole of ethanol present in the beaker is 0.217 mole

Description of mole
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass

How to determine the mole of C₂H₅OH
From the question given above, the following data were obtained:
Mass of C₂H₅OH = 10 g
Molar mass of C₂H₅OH = (12×2) + (1.01×5) + 16 + 1.01 = 46.06 g/mol
Mole of C₂H₅OH =?

Mole = mass / molar mass
Mole of C₂H₅OH = 10 / 46.06
Mole of C₂H₅OH = 0.217 mole


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brainly.com/question/13314627

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5 0
2 years ago
What makes an ionic compound an ionic compound?
zalisa [80]
An ionic compound can be formed through the existence of valency above the compound e.g NH4 which have +3 as it's ionic charge
6 0
3 years ago
The decomposition of dinitrogen pentoxide, N2O5, to NO2 and O2 is a first-order reaction. At 60°C, the rate constant is 2.8 × 10
Sati [7]

Answer:

a. 113 min

Explanation:

Considering the equilibrium:-

                   2N₂O₅ ⇔ 4NO₂ + O₂

At t = 0        125 kPa

At t = teq     125 - 2x      4x        x

Thus, total pressure = 125 - 2x + 4x + x = 125 - 3x

125 - 3x = 176 kPa

x = 17 kPa

Remaining pressure of N₂O₅ = 125 - 2*17 kPa = 91 kPa

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 2.8\times 10^{-3} min⁻¹

Initial concentration [A_0] = 125 kPa

Final concentration [A_t] = 91 kPa

Time = ?

Applying in the above equation, we get that:-

91=125e^{-2.8\times 10^{-3}\times t}

125e^{-2.8\times \:10^{-3}t}=91

-2.8\times \:10^{-3}t=\ln \left(\frac{91}{125}\right)

t=113\ min

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2 years ago
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