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Goshia [24]
3 years ago
13

I need help ASAP I’ll give brainliest:)

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

Volume of the cone:

V = 3.14 x 3^2 x 9/3 = 84.78

Volume of half sphere on top of cone:

V = (4/3 x 3.14 x 3^3 )/2 = 56.52

Total volume = 56.52 + 84.78 = 141.3 cm^3

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1/2r -3= 3 (4-3/2r) solve for r
s2008m [1.1K]

1/2r -3= 3 (4-3/2r) is to be solved for r.


I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.


Thus, 1/2r -3= 3 (4-3/2r) becomes (1/2)r -3= 3 (4-(3/2)r ) .

Simplify this by multiplying all 3 terms by 2. Doing this will eliminate the fractions:


r -6 = 3 (4*2-(3)r ) or r - 6 = 24 - 9r


Now expand the right side, using the distributive property of

r - 3 = 24 - 9r


Regrouping so as to combine like terms:


10r = 30


Solving for r: r = 30/10 = 3


The value of r that satisfies this equation is 3

8 0
3 years ago
HELP MEE PLEASE HELP
SOVA2 [1]

Answer:

42.75

Step-by-step explanation:

area of one piece, length x width:    3 x 4 3/4

                                                                14.25

area of 3 pieces:   14.25(3)= 42.75

8 0
2 years ago
I need help getting the answer could you help me by chance to receive brainlest!?
Pani-rosa [81]
(Placeholder because it won’t let me ask more questions until I answer some)
5 0
3 years ago
-3x=x-(6-2x) solve it
frutty [35]

Answer:

x=1

Step-by-step explanation:

-3x=x-(6-2x)

-3x=x-6+2x

-3x=3x-6

6=3x+3x

6=6x

x=6/6

x=1

Best answer if it helped, please

3 0
3 years ago
7+3√5/3+√5 - 7-3√5/3-√5 = a + b√5
daser333 [38]
<h3>Given:-</h3>

\\ \sf \implies\frac{7 + 3 \sqrt{5} }{3 +  \sqrt{5} }  -  \frac{7  - 3 \sqrt{5} }{3  -   \sqrt{5} }  = a +  \sqrt{5} b \\

<h3>To Find:-</h3>

  • The value of a and b

<h3>Solution:-</h3>

\\ \sf \implies\frac{7 + 3 \sqrt{5} }{3 +  \sqrt{5} }  -  \frac{7  - 3 \sqrt{5} }{3  -   \sqrt{5} }  = a +  \sqrt{5} b \\

\\ \sf \implies\frac{( \: 7 + 3 \sqrt{5} \:  \: (  3  -   \sqrt{5}) \:  \:  - 7  -  3 \sqrt{5} \:  \: (  3   +    \sqrt{5}) \: }{(3 +  \sqrt{5})  \:  \:(3 +  \sqrt{5}) }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{( \: 21 - 7 \sqrt{5} \:   +  9    \sqrt{5} - 15) \:  \:  - ( \: 21  + 7 \sqrt{5} \:    -  9    \sqrt{5}  +  15)\: }{(3 +  \sqrt{5})  \:  \:(3 +  \sqrt{5}) }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{( \: 6 + 2 \sqrt{5} ) \:  \:  - ( \: 6 - 2 \sqrt{5} )\: }{(3 +  \sqrt{5})  \:  \:(3 +  \sqrt{5}) }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: 6 + 2 \sqrt{5}  \:  \:  -  \: \: 6 - 2 \sqrt{5} \: }{(3 +  \sqrt{5})  \:  \:(3 +  \sqrt{5}) }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: 4 \sqrt{5}  \:  \:   }{3  {}^{2}   -  {\sqrt{5} }^{2}  }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: 4 \sqrt{5}  \:  \:   }{ \:  \:  \:  \: 9 - 5 \:  \:  \:   }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: 4 \sqrt{5}  \:  \:   }{ \:  \:  \:  \: 4 \:  \:  \:   }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: \cancel{4 } \sqrt{5}  \:  \:   }{ \:  \:  \:  \:  \cancel{4 }\:  \:  \:   }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies \: \sqrt{5}  = a +  \sqrt{5}  \:  b\\

we can also write it as ;

\\ \sf \implies \: 0 + \sqrt{5}  = a +  \sqrt{5}  \:  b\\

★<u> </u><u>Henceforth, the value of a and b are</u> :

→ a = 0

→ b = 1

6 0
2 years ago
Read 2 more answers
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