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Goshia [24]
3 years ago
13

I need help ASAP I’ll give brainliest:)

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

Volume of the cone:

V = 3.14 x 3^2 x 9/3 = 84.78

Volume of half sphere on top of cone:

V = (4/3 x 3.14 x 3^3 )/2 = 56.52

Total volume = 56.52 + 84.78 = 141.3 cm^3

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Find the midpoint of the segment with the given endpoints K(-2,-4) and L(-4,6)
Ilia_Sergeevich [38]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ K(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad L(\stackrel{x_2}{-4}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-4-2}{2}~~,~~\cfrac{6-4}{2} \right)\implies \left( \cfrac{-6}{2}~~,~~\cfrac{2}{2} \right)\implies (-3~,~1)

8 0
3 years ago
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Please help, its urgent. (Question Below)
rusak2 [61]

The highest common factor of the numbers 210 and 308 is 4.

<h3>What is the highest common factor?</h3>

The highest factor of the two numbers which divides both the numbers is called as greatest common factor or HCF.

The highest common factor will be calculated by finding the factors of the two numbers. The factors of the two numbers are as follows:-

308   =  2 x  2   x  7  x  11

210   =  2  x  2   x  3  x  17

We can see that the 2  x  2  =  4 is the highest factor which is common between the two numbers 210 and 308. So 4 is the HCF which can divide both the numbers 210 and 308.

Therefore the highest common factor of the numbers 210 and 308 is 4.

To know more about HCF follow

brainly.com/question/219464

#SPJ1

4 0
2 years ago
Graph the equation by translating Y =|x|. Y=|x+1|-3
goldenfox [79]

Answer:

look at the graph i made with desmos, i just plugged the equation in.

Step-by-step explanation:

6 0
3 years ago
Find the value of A if the 4-digit number 3A5A is divisible by both 3 and 5.
Arturiano [62]

Answer:

The value of A is 5

Step-by-step explanation:

- The number is divisible by 3 if the sum of its digits is a number

  divisible by 3

- Ex: 126 is divisible by 3 because the sum of its digits = 1 + 2 + 3 = 6

  and 6 is divisible by 3

- The number is divisible by 5 if its ones digit is zero or 5

- Ex: 675 is divisible by 5 because its ones digit is 5

        890 is divisible by 5 because its ones digit is 0

- We are looking for the value of A in the 4-digit number 3A5A which

  makes the number divisible by both 3 and 5

∵ A is in the ones position

∴ A must be zero or 5

- Let us try A = 0

∵ A = 0

∴ The number is 3050

∵ The sum of the digits of the number = 3 + 0 + 5 + 0 = 8

∵ 8 is not divisible by 3

∴ 3050 is not divisible by both 3 and 5

∴ A can not be zero

- Let us try A = 5

∵ A = 5

∴ The number is 3555

∵ The sum of the digits of the number = 3 + 5 + 5 + 5 = 18

∵ 18 is divisible by 3

∴ 3555 is divisible by both 3 and 5

∴ A must be equal 5

* <em>The value of A is 5</em>

5 0
3 years ago
Help (the answer isn't the 2nd one my friend did this test and chose that and got it wrong please )
Artyom0805 [142]

Answer: 4 and 3/5

Step-by-step explanation:

7 0
2 years ago
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