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3 years ago

What are fragments of dust, soil, salt, smoke and ash upon which water vapor condenses to make clouds

2 answers:

8 0

Particles of dust, soil, fecal matter, metals, salt, smoke, ash, and other solids makeup a small percentage of the atmosphere and are called particulates. Particles provide starting points (or nuclei) for water vapor to condense on and form raindrops. Some particles are pollutants.

SVEN [57.7K]3 years ago

6 0

Answer:

Particulate matter

Explanation:

The particulate matters are defined as the aerosol particles that are found to be present freely in the atmosphere. They are the mixture of dust, soil, salt, liquid drops, smoke and ashes. They can be formed both naturally and from the anthropogenic activities. These smaller particles present in the water vapor undergoes condensation, forming liquid and ice on the surfaces of dust particles present in the atmosphere. With more frequent condensation of water vapor, results in the formation of clouds.

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Natasha2012 [34]

Answer:

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Explanation:

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2 years ago

Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili

Katen [24]

Answer: The value of equilibrium constant for the given reaction is 56.61

Explanation:

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

$\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}$

$\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M$

$\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M$

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

$H_2+I_2\rightleftharpoons 2HI$

Initial: 0.1 0.1

At eqllm: 0.1-x 0.1-x 2x

Evaluating the value of 'x'

$\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

$[HI]_{eq}=2x=(2\times 0.079)=0.158M$

$[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M$

$[I_2]_{eq}=0.0210M$

Putting values in above expression, we get:

$K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61$

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0

3 years ago

In which list are the elements arranged in order of increasing atomic mass?(1) Cl, K, Ar (3) Te, I, Xe(2) Fe, Co, Ni (4) Ne, F,

galina1969 [7]

Answer: 1

1.Cl K Ar is in order

2.Fe Co Ni isn't in order

3.Te I Xe isn't in order

4.Ne F Na isn't in order

4 0

2 years ago

Need help balancing equations

Reptile [31]

The answers is 2 1 4 3

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2 years ago

Do light waves interact with all mediums the same?

jeka94

Answer:

Light can be reflected, transmitted, or absorbed. You have read that EM waves can interact with a material medium in the same ways that mechanical waves do.

Explanation:

7 0

2 years ago

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